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slava [35]
3 years ago
7

How many atoms in total are there in 7.35 mol of magnesium oxide (MgO) molecules?

Chemistry
1 answer:
andreev551 [17]3 years ago
3 0

Answer:

4.42 x 10^24

Explanation:

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4 When the net force on an object is zero, we say that the two forces are:
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Identify the reactants and the products in the following chemical equation. Cd(NO^3)^2+(aq)+H^2S(g)-->Cds(s)+2HNO^3(aq)
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8 0
3 years ago
Calculate the amount of heat energy in KJ required to convert 45.0 g of ice at -15.5'C to steam at 124.0°C. (Cwater 118 Jig'c, G
dangina [55]

Answer : The enthalpy change or heat required is, 139.28775 KJ

Solution :

The conversions involved in this process are :

(1):H_2O(s)(-15.5^oC)\rightarrow H_2O(s)(0^oC)\\\\(2):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(3):H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)\\\\(4):H_2O(l)(100^oC)\rightarrow H_2O(g)(100^oC)\\\\(5):H_2O(g)(100^oC)\rightarrow H_2O(g)(124^oC)

Now we have to calculate the enthalpy change.

\Delta H=[m\times c_{p,s}\times (T_{final}-T_{initial})]+n\times \Delta H_{fusion}+[m\times c_{p,l}\times (T_{final}-T_{initial})]+n\times \Delta H_{vap}+[m\times c_{p,g}\times (T_{final}-T_{initial})]

where,

\Delta H = enthalpy change or heat required = ?

m = mass of water = 45 g

c_{p,s} = specific heat of solid water = 2.09J/g^oC

c_{p,l} = specific heat of liquid water = 4.18J/g^oC

c_{p,g} = specific heat of liquid water = 1.84J/g^oC

n = number of moles of water = \frac{\text{Mass of water}}{\text{Molar mass of water}}=\frac{45g}{18g/mole}=2.5mole

\Delta H_{fusion} = enthalpy change for fusion = 6.01 KJ/mole = 6010 J/mole

\Delta H_{vap} = enthalpy change for vaporization = 40.67 KJ/mole = 40670 J/mole

Now put all the given values in the above expression, we get

\Delta H=[45g\times 4.18J/gK\times (0-(-15.5))^oC]+2.5mole\times 6010J/mole+[45g\times 2.09J/gK\times (100-0)^oC]+2.5mole\times 40670J/mole+[45g\times 1.84J/gK\times (124-100)^oC]

\Delta H=139287.75J=139.28775KJ     (1 KJ = 1000 J)

Therefore, the enthalpy change is, 139.28775 KJ

3 0
3 years ago
Given x g of a substance that has a molar mass of y g/mol, which operation will give an answer with units of moles?
Kryger [21]

To calculate moles of any \text{x grams} of a subtance, we need to divide the given mass by the molar mass of the substance that is \text{y grams/mol} given as per the question. By simply putting the values of the two masses we will be left with the number of moles of the given substance.

n=\frac{m}{M}

where, n= number of moles of given substance (mol)

m= given mass of the substance (grams)

M= molar mass of the given substance (grams/mol)

6 0
3 years ago
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