Are babies producers or consumers or none? What about rocks? Are they producers or consumers?

1 Balance each equation. Paragraph Styles Voice Sensity 2) Indicate the type of reaction by classifying each reaction as single

nika2105 [10]

1. Double replacement (DR)

2. Decomposition (D)

<h3>Further explanation</h3>

1. Al2(SO4)3 + Ca3(PO4)2 -> 2AIPO4 + 3CaSO4

Double replacement (DR) : there is an ion exchange between two ion compounds in the reactant to form two new ion compounds in the product

General form :

AB + CD -> AD + CB

2. 2NaCIO3 → 2NaCl + 3O2

Decomposition (D) : Reactant breakdown into simpler ones(reverse of combination)

General form :

AB ---> A + B

6 0

3 years ago

Which chloride is a coloured solid rtp<br>

lianna [129]

Answer:

sodium chloride

hope that helped :)

7 0

2 years ago

Read 2 more answers

Lighting a match changes ch and energy into heat.

otez555 [7]

Answer:

The answer remains the same. The total amount of energy stays the same because the 1st Law of Thermodynamics states that energy can neither be created nor destroyed, it can only change forms. So the chemical energy is just being converted into heat and light.

Explanation:

hope this helps...

7 0

3 years ago

A 0.4647-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in oxygen to yield 0.01962 mol of

Stella [2.4K]

Answer:

See explanation.

Explanation:

Hello,

In this case, we can show how the empirical formula is found by following the shown below procedure:

1. Compute the moles of carbon in carbon dioxide as the only source of carbon at the products:

$n_C=0.01962molCO_2*\frac{1molC}{1molCO_2} =0.01962molC$

2. Compute the moles of hydrogen in water as the only source of hydrogen at the products:

$n_H=0.01961molH_2O*\frac{2molH}{1molH_2O}=0.03922molH$

3. Compute the mass of oxygen by subtracting the mass of both carbon and hydrogen from the 0.4647-g sample:

$m_O=0.4647g-0.01962molC*\frac{12gC}{1molC}-0.03922molH*\frac{1gH}{1molH} =0.1900gO$

4. Compute the moles of oxygen by using its molar mass:

$n_O=0.1900gO*\frac{1molO}{16gO}=0.01188molO$

5. Divide the moles of carbon, hydrogen and oxygen by the moles of oxygen (smallest one) to find the subscripts in the empirical formula:

$C=\frac{0.01962}{0.01188}=1.65\\ \\H=\frac{0.03922}{0.01188} =3.3\\\\O=\frac{0.01188}{0.01188} =1$

6. Search for the closest whole number (in this case multiply by 2):

$C_3H_6O_2$

Moreover, the empirical formula suggests this compound could be carboxylic acid since it has two oxygen atoms, nevertheless, this is not true since the molar mass is 222.27 g/mol, therefore, we should compute the molar mass of the empirical formula, that is:

$M=12*3+1*6+16*2=74g/mol$

Which is about three times in the molecular formula, for that reason, the actual formula is:

$C_9H_{18}O_6$

It suggest that the compound has a highly oxidizing character due to the presence of oxygen, therefore, we cannot predict the distribution of the functional groups as it could contain, carboxyl, carbonyl, hydroxyl or even peroxi.

Best regards.

6 0

3 years ago

The solvolysis of t-butyl bromide in methanol yields 2-methylpropene in an E1 reaction (among other products). What is the effec

jolli1 [7]

Answer:

See explanation

Explanation:

For a reaction that proceeds by E1 mechanism, the rate determining step involves the formation of the carbocation.

The rate of formation of this carbocation depends only on the concentration of the t-butyl bromide since it is the only specie that enters into the rate equation.

Hence, when the concentration of t-butyl bromide is tripled, the rate of reaction is tripled.

Methanol does not enter into the rate equation hence doubling its concentration does not affect the rate of reaction.

7 0

2 years ago