I believe this is the a^2+b^2=c^2. Sorry if you don't understand me language I speak German. But uh, its based on PT i think. hope it help!
Molality is defined as the number of moles of solute present in 1L of solution.
Molality (M) = No of moles of solute / 1 L of solution
Litre of solution = No of moles of solute / Molality
Molality = 0.220M
No of moles= 0.0170 mol
Volume in L = 0.0170/0.220
= 0.0772 L
Volume in mL = 77.27 mL
What is mole?
- A mole is a very important unit of measurement used by chemists.
- moles of something means there are 602,214,076,000,000,000,000,000,000,000,000 number of something.
- Chemists need to measure very small things such as atoms, molecules and other particles in moles.
- 602,214,076,000,000,000,000,000 is called Avogadro's number, abbreviated as 6.02 x
Therefore, Volume in ml of 0.220 m hbr solution is required to produce 0.0170 moles is 77.27 mL.
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The balanced equation for the above reaction is as follows;
C + H₂O ---> H₂ + CO
stoichiometry of C to H₂O is 1:1
1 mol of C reacts with 1 mol of H₂O
we need to find which is the limiting reactant
2 mol of C and 3.1 mol of H₂O
therefore C is the limiting reactant and H₂O is in excess.
stoichiometry of C to H₂ is 1:1
then number of H₂ moles formed are equal to C moles reacted
number of H₂ moles formed = 2 mol
Answer:
The heat of reaction -1.9 kilo Joules.
Explanation:
Volume of the hydrogen peroxide solution = 50.0 mL
Volume of the ferric nitrate solution = 10.0 mL
Total volume of the solution = 50.0 mL + 10.0 mL = 60.0 mL
Mass of the final solution = m
Density of water = density of the final solution = d = 1 g/mL
Heat capacity of the mixture = c = 4.18 J/g°C
Change in temperature of the mixture = ΔT = 7.47°C
Heat absorbed by the mixture = Q
Heat release due to reaction = -Q'
-Q' =Q (law of conservation of enrage)
Q'= -Q = -1.9 kJ
The heat of reaction -1.9 kilo Joules.
E°cell =+1.34V
F= 96485C mol-1
3Cu(s) →3CU2+(aq) +6e-E°ck= -0.34V
2MnO4-(aq) +8H+(aq)+6e→2MnO2(s)+4H2O(l)/3CU(s) + 2MnO4-(aq)+8H+(aq)→3CU 2+((aq)+ 2MnO2(s)+4H2O (l)
E°red= +1.68V/E°cell=+1.34V
ΔG° = -nFE°cell = -6×96485×1.34 = -775.7kJ/mol