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Tom [10]
3 years ago
8

Can some one help whith these

Chemistry
2 answers:
Dmitry [639]3 years ago
7 0

Answer:

hlo we can't see ur pdf so sry

plz mark me as a brainliest

MA_775_DIABLO [31]3 years ago
5 0

Answer:

what is this pdf I cannot see your question

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Sand is converted to pure silicon in a three step process. the third step is sicl4(g) + 2mg(s) → 2mgcl2(s) + si(s) δh = –625.6 k
JulijaS [17]
The reaction is that,
1 mole is SiCL4 will produce 1 mole of Si(s) Since there is 1 to 1 relationship then we just multiply the enthalpy of reaction by the number of moles
Enthalpy = -625.5 kJ/mole × 12.5 Moles 
= -7,818.75 KJ
= -0.78 ×10⁴KJ
5 0
4 years ago
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The density of an object is 1.23 g/cm3. In which of the following materials will it float?
BartSMP [9]
In order to float the demsoty of the floating obkect must be lower then the liquid it is in. the only one that works for is Citric acid
7 0
3 years ago
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Determine the number of ions produced in the dissociation of the compound listed. BaS
11Alexandr11 [23.1K]
BaS → Ba²⁺ + S²⁻
two types of ions
4 0
4 years ago
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Suppose that coal of density 1.5 g/cm^3 is pure carbon. (It is, in fact, much more complicated, but this is a reasonable first a
NISA [10]

Answer:

q = -6464.9 kJ

Explanation:

We are given that the heat of combustion is  ∆H° = −394 kJ per mol of carbon.Therefore what we need to do is calculate how many moles of C are in the lump of coal by finding its mass since the density is given.

vol = 5.6 cm x 5.1 cm x 4.6 cm = 131.38 cm³

m = d x v = 1.5 g/cm³ x 131.38 cm³ = 197.06 g

mol C = m/MW = 197.06 g/ 12.01g/mol = 16.41 mol

q =  −394 kJ /mol C x 16.41 mol C = -6464.9 kJ

7 0
3 years ago
The partial pressures of the gases in a mixture are 0.255 atm 0, 3.24 atm Ny,
katovenus [111]
<h3>Answer:</h3>

4.945 atm

<h3>Explanation:</h3>
  • Based on Dalton's law of Partial pressure, the total pressure of a mixture of gases is equivalent to the sum of individual partial pressures of the gases in the mixture.
  • That is;

Pt = P1+P2+P3+P4+............+ Pn

In this case;

Partial pressure of Oxygen, P(O) = 0.255 atm

Partial pressure of N, P(N) = 3.24 atm

Partial pressure of Ar, P(Ar) = 1.45 atm

Therefore;

P(total) = P(O) + P(N) + P(Ar)

           = 0.255 atm + 3.24 atm + 1.45 atm

           = 4.945 atm

Therefore, the total pressure of the mixture is 4.945 atm

6 0
4 years ago
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