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Elis [28]
2 years ago
6

A group of students working in a chemistry lab are planning a procedure to

Chemistry
1 answer:
NARA [144]2 years ago
4 0

use a strong base to neutralize, like NaOH, KOH, etc

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Which type of galaxy has a central bar of stars instead of a rounded core? A. spiral B. irregular C. elliptical D. barred spiral
Art [367]

the answer is D. Barred Spiral

8 0
3 years ago
Which scenario ensures that Earth’s global temperature is maintained?
Bond [772]

Answer:

Explained below:

Explanation:

The global temperature means the fluctuations in the temperature of the atmosphere and the oceans (existing in the earth surface).

Is the Earth’s global temperature is maintained or not depends on how much sunlight hits Earth versus and how much is returned, it also depends on the atmospheric level of carbon dioxide which prevents the earth from extreme cooling during the night.

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3 years ago
one of the isotopes of sulfur is represented as sulfur -35 or S-35. what does the number 35 signify?
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35 is equal to it's mass number
6 0
4 years ago
Read 2 more answers
When we mix aqueous solutions of silver nitrate and sodium chloride, a white precipitate of silver chloride forms in the reactio
zloy xaker [14]

Answer:

solid substance formed during liquid solution, is known as precipitate. For example: in the reaction of silver nitrate and sodium chloride, a precipitate of silver chloride is formed which is white in colour. Precipitation can be of any colour like white, yellow, black.

6 0
3 years ago
Combustion of hydrocarbons such as butane () produces carbon dioxide, a "greenhouse gas." Greenhouse gases in the Earth's atmosp
Dahasolnce [82]

Answer:

1. C₄H₁₀ + ¹³/₂O₂ → 4CO₂ + 5H₂O

2. V = 596L

Explanation:

Butane (C₄H₁₀) reacts with oxygen (O₂) to produce carbon dioxide (CO₂) and water (H₂O) thus:

C₄H₁₀ + O₂ → CO₂ + H₂O

1. The balanced chemical equation is:

C₄H₁₀ + ¹³/₂O₂ → 4CO₂ + 5H₂O

2. 0,360kg of butane are:

360g×\frac{1mol}{58,12g}=<em>6,19moles of butane</em>

These moles of butane are:

6,19moles of butane×\frac{4CO_2}{1molButane}= <em>24,8 moles CO₂</em>

Using V=nRT/P

Where:

n are moles (24,8 moles CO₂); R is gas constant (0,082atmL/molK); T is temperature, 20°C (293,15K); and P is pressure (1atm).

Volume (V) is:

<em>V = 596L</em>

I hope it helps!

8 0
4 years ago
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