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docker41 [41]
3 years ago
5

An element X forms a compound XH 3 with hydrogen. Another element Y forms a compound YX 2 with X. Given that the valency of hydr

ogen is 1, What are the valencies of X &Y?
Chemistry
1 answer:
Marina CMI [18]3 years ago
7 0
XH_{3}
H has a positive 1 charge. This means that having 3H = +3<span>.  This is a neutral compound so x= -3 because X+3H= 0

Y</span>X_{2} is also neutral so 2X+Y= 0
we know X=-3 So, 2(-3)+Y=0
-6+y=0
Y=+6 charge

 
Answer: The valency of X is -3. The valency of Y is 6
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A 22.2 g sample of MgCl2 is dissolved in water, creating a solution with a mole fraction of 0.0500 moles of MgCl2 per mole of so
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This problem is providing both the mole fraction and mass of magnesium chloride in an aqueous solution. Thus, the total moles of the solution are required and turned out to be 4.62 moles.

<h3>Mole fraction</h3>

In chemistry, units of concentration are used to account for the relative amounts of solute and solvent in solid, liquid or even gaseous solutions.

Thus, several units are widely employed, yet this problem is about mole fraction, which relates the moles of the solute and the total moles of the solution as follows:

x=\frac{n_{solute}}{n_{total}}

Hence, given the mass of the solute, calcium chloride, we can calculate its moles as follows:

n_{solute}=22.2g*\frac{1mol}{95.21g}=0.231mol

Thereafter, we solve for the total moles of the solution and subsequently plug in the knowns:

n_{total}=\frac{n_{solute}}{x}\\\\n_{total}=\frac{0.231mol}{0.0500}\\\\n_{total}=4.62mol

Learn more about mole fraction: brainly.com/question/2060778

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2 years ago
Hi, I need help on the chemical names of the following two:
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Answer:

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3 0
3 years ago
Why is soap able to break down oils and fats?
sergiy2304 [10]

Answer:

When you build up a soapy lather, the molecules help lift the dirt, oil and germs from your skin

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3 0
3 years ago
How much ice (in grams) would have to melt to lower the temperature of 353 mL of water from 26 ∘C to 6 ∘C? (Assume the density o
Rashid [163]

Answer:

The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg

Explanation:

Heat gain by ice = Heat lost by water

Thus,  

Heat of fusion + m_{ice}\times C_{ice}\times (T_f-T_i)=-m_{water}\times C_{water}\times (T_f-T_i)

Where, negative sign signifies heat loss

Or,  

Heat of fusion + m_{ice}\times C_{ice}\times (T_f-T_i)=m_{water}\times C_{water}\times (T_i-T_f)

Heat of fusion = 334 J/g

Heat of fusion of ice with mass x = 334x J/g

For ice:

Mass = x g

Initial temperature = 0 °C

Final temperature = 6 °C

Specific heat of ice = 1.996 J/g°C

For water:

Volume = 353 mL

Density (\rho)=\frac{Mass(m)}{Volume(V)}

Density of water = 1.0 g/mL

So, mass of water = 353 g

Initial temperature = 26 °C

Final temperature = 6 °C

Specific heat of water = 4.186 J/g°C

So,  

334x+x\times 1.996\times (6-0)=353\times 4.186\times (26-6)

334x+x\times 11.976=29553.16

345.976x = 29553.16

x = 85.4197 kg

Thus,  

<u>The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg</u>

7 0
4 years ago
If a 50 N force pulls on a 10 kg object,how much acceleration will occur?
meriva
Assuming that the force of friction does not equal to the force at which you are pulling at, hence Fnet is not zero, to solve for acceleration need to use the following equation:

Fnet = ma
a = Fnet/m
a = 50 N/10 kg
a = 5 N/kg or a = 5 m/s^2.
4 0
3 years ago
Read 2 more answers
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