How many Neutrons are in a ^15N isotope?

Given its reactive nature, oxygen is essential to cellular metabolic reactions. Peroxisomes use oxygen to break down fatty acids

marysya [2.9K]

Answer:

Catalase

Explanation:

These reactive oxygen specie or free radicals that cause damage or injury to cells also lead to oxidative stress if unchecked by antioxidants. As suggested in the question, there are several enzymes that act as antioxidants in mitigating the effects of these reactive oxygen specie or free radicals. These enzymes include catalase, superoxide dismutase and glutathiones (such as glutathione s-transferase).

The enzyme that however prevents the accumulation of hydrogen peroxide (H₂O₂) in the peroxisome is catalase. Catalase is an enzyme that is present in the peroxisome; it (catalase) detoxifies/acts on H₂O₂, converting it (H₂O₂) into water and oxygen.

4 0

3 years ago

How many atoms are in 3.2 moles of chromium?

-BARSIC- [3]

Hey there!

1 mole has 6.022 x 10²³ atoms.

Multiply that by 3.2 because we have 3.2 moles.

3.2 x 6.022 x 10²³

1.9 x 10²⁴

There are 1.9 x 10²⁴ atoms in 3.2 moles of chromium.

Hope this helps!

3 0

3 years ago

What factors could have affected your results?

AleksandrR [38]

Answer:

See below

Step-by-step explanation:

heat gained by metal + heat lost by water = 0

m₁C₁ΔT₁ + m₂C₂ΔT₂ = 0

C₁ = -(m₂C₂ΔT₂)/(m₁ΔT₁)

The factors determining C₁ are

mass of water
temperature change of water (T_f - Ti)
mass of metal
temperature change of metal (T_f - Ti)

Any factor that makes the numerator higher or the denominator lower than what you thought, will give a calculated C₁ that is too high (and vice versa).

The major sources of uncertainty are probably in determining the temperatures, especially the initial and final temperatures of the metal. However, you will have to decide what the principal factors were in your experiment.

For example, did the metal have a chance to cool during the transfer to the calorimeter? How easy was it to determine the equilibrium temperature, etc?

Factors Affecting the Calculation of Specific Heat Capacity

Water Water

Mass less than thought Mass more than thought

Ti lower Ti higher

T_f higher T_f lower

Metal Metal

Mass more than thought Mass less than thought

Ti higher Ti lower

8 0

3 years ago

ethylene glycol, commonly used in automobile antifreeze, contains only carbon, hydrogen and oxygen.combustion analysis of a 23.4

Kay [80]

Answer:

Molecular formula of ethylene glycol is C₂H₆O₂.

Explanation:

Given data:

mass of ethylene glycol = 23.4 mg

mass of water = 20.42 mg

mass of carbon dioxide = 33.27 mg

molar mass of ethylene glycol = 62.0 g / mol

Molecular formula of ethylene glycol = ?

Solution:

percentage of carbon = (33.27 mg/ 23.46 mg) × (12 /44) × 100

= (1.4182× 0.27) × 100 = 38.29

percentage of hydrogen = (20.42 mg/ 23.46 mg) × (2 /18) × 100

= (0.8704× 0.11) × 100 = 9.67

percentage of oxygen = 100 - (38.29 + 9.67 )

= 100 - 47.96 = 52.04

Now we will determine the number of grams atoms of carbon, hydrogen and oxygen.

No. of gram atoms of carbon = 38.29 /12 = 3.19

No. of gram atoms of hydrogen = 9.67 / 1 = 9.67

No. of gram atoms of oxygen = 52.04 / 16 = 3.25

Atomic ratio:

C :H :O 3.19/ 3.19 : 9.67 / 3.19 : 3.25 /3.19

C :H :O 1 : 3 : 1

Molecular formula:

Molecular formula = n × (empirical formula)

n = molar mass of compound / empirical formula mass

empirical formula mass= 1 × 12 + 3 × 1 + 1 × 16

empirical formula mass= 12+3 +16 = 31

n = 62 g /mol / 31 = 2

Molecular formula = n × (empirical formula)

Molecular formula = 2 × (CH₃O)

Molecular formula = C₂H₆O₂

6 0

3 years ago

In a test of an automobile engine 1.00 L of octane (702 g) is burned, but only 1.84 kg of carbon dioxide is produced. What is th

Reptile [31]

Answer:

The % yield of CO2 is 85.05 %

Explanation:

Step 1: Data given

Mass of octane = 702 grams

Molar mass octane = 114.23 g/mol

Mass CO2 =1.84 kg = 1840 grams

Molar mass of CO2

Step 2: The balanced equation

2C8H18 + 25O2 → 16CO2 + 18H2O

Step 3: Calculate moles of octane

Moles octane = mass octane / molar mass octane

Moles octane = 702.0 grams / 114.23 g/mol

Moles octane = 6.145 moles

Step 4: Calculate moles of CO2

For 2 moles octane we need 25 moles O2 to produce 16 moles CO2 and 18 moles H2O

For 6.145 moles octane we'll have 8*6.145 moles =49.16 moles

Step 5: Calculate mass of CO2

Mass CO2 = moles CO2 * molar mass CO2

Mass CO2 = 49.16 moles * 44.01 g/mol

Mass CO2 = 2163.5 grams

Step 6: Calculate % yield of carbon dioxide

% yield = (actual yield / theoretical yield)*100%

% yield = (1840/2163.5)*100%

% yield = 85.05 %

The % yield of CO2 is 85.05 %

4 0

3 years ago