How many Neutrons are in a ^15N isotope?

When silver coins are found in ancient shipwrecks,they are coated with a black crust. What question could you ask to help you de

leonid [27]

It went under a physical change because it (1) changed color. (2) changed form.

8 0

3 years ago

How much heat is lost when 1277 g of H20 at 400 K is changed into ice at 263 K? Plz help I’ll give you brainliest 20 points

OLga [1]

The heat lost is $-7.32*10^-^5J$

The heat lost when the ice is cooled from 400k to 263K can be calculated using the formula of heat transfer.

<h3>Heat Transfer</h3>

This is the heat transferred from a body of higher temperature to a body of lower temperature.

$Q = mc(\delta)T$

Q = Heat Transfer
m = mass = 1277g
ΔT = change in temperature

$\delta T = (400 - 273) - (263 - 273) = \\
\delta T = T_2 - T_1\\
\delta T = -10 - 127\\
\delta T = -137^0C$

We converted the temperature from kelvin scale into Celsius scale and find the change in temperature.

Solving for heat transfer

$Q = mc\delta T\\
Q = 1277 * 4.186 * -137\\
Q = -732336.514J$

The heat loss is approximately $-7.32*10^-^5J$

Learn more on heat transfer here;

brainly.com/question/16055406

6 0

2 years ago

. Though Florida receives a lot of rainfall, only 1 percent remains available for people to use or drink. What happens to the re

monitta

1st part.)). The rest of the water goes into oceans and underground.

8 0

3 years ago

What mass of FeSO4^2- x 6H20 (Molar Mass=260g/mol) is required to produce 500 mL of a .10M iron (II) sulfate solution.

lukranit [14]

Answer:

The correct option is: B. 13g

Explanation:

Given: Molar mass of iron (II) sulfate: m = 260g/mol,

Molarity of iron (II) sulfate solution: M = 0.1 M,

Volume of iron (II) sulfate solution: V = 500 mL = 500 × 10⁻³ = 0.5 L (∵ 1L = 1000mL)

Mass of iron (II) sulfate taken: w = ? g

<em>Molarity</em>: $M = \frac{n}{V (L)} = \frac{w}{m\times V(L)}$

Here, n- total number of moles of solute, w - given mass of solute, m- molar mass of solute, V- total volume of solution in L

∴ <em>Molarity of iron (II) sulfate solution:</em> $M = \frac{w}{m\times V(L)}$

⇒ $w = M\times m\times V(L)$

⇒ $w = (0.1 M)\times (260g/mol)\times (0.5L)$

⇒ <em>mass of iron (II) sulfate taken:</em> $w = 13 g$

<u>Therefore, the mass of iron (II) sulfate taken for preparing the given solution is 13 g.</u>

5 0

3 years ago

Which group on the periodic table contains only metals? A. the second group B. Along the top C. Along the bottom D. The last gro

Mrac [35]

Good day sir, I believe it is C Have a great day!

8 0

2 years ago