According to half life equation:
T(1/2) = ㏑2 / K1
when the T(1/2) = 4 min * 60 = 240 sec
by substitution:
240 = 0.6931 / K1
K1 = 2.9 x 10^-3
when the second T(1/2) = 20 sec, so to get K2:
T(1/2) = 0.6931 / K2
by substitution:
20 = 0.6931 / K2
∴K2 = 3.4 x 10^-2
so, we can get T2 by using this formula:
㏑ (K2/K1) = Ea/R (1/T1 - 1/T2)
by substitution:
㏑(3.4 x 10^-2)/(2.9 x 10^-3) = (24520 / 8.314) (1/298 - 1/T2)
∴ T2 = 396.7 K
= 396.7 - 273 = 123.7 °C
Decomposition is a part of the carbon cycle that occurs slowly hence movement of carbon dioxide into the atmosphere when bacteria decomposes dead matter is a slow part of the carbon cycle.
<h3>What is the carbon cycle?</h3>
The carbon cycle is part of the biogeochemical cycles that exist in nature. It refers to the movement of carbon in the ecosystem. The carbon cycle cuts across the air, the land and the water bodies.
The process in the carbon cycle that occurs slowly among the options is the movement of carbon dioxide into the atmosphere when bacteria decomposes dead matter.
Learn more about carbon cycle: brainly.com/question/1627609
It’s C I hope this was useful and have a great day!
Unicellular
multicultural is usually found in loving things like plants or animals
Answer:
630.95 grams of Na₂CO₃ would be needed to produce 1000g of NaHCO₃
Explanation:
The balanced reaction is:
Na₂CO₃ + CO₂+ H₂O → 2 NaHCO₃
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:
- Na₂CO₃: 1 moles
- CO₂: 1 mole
- H₂O: 1 mole
- NaHCO₃: 2 moles
Being the molar mass:
- Na₂CO₃: 106 g/mole
- CO₂: 44 g/mole
- H₂O: 18 g/mole
- NaHCO₃: 84 g/mole
Then by stoichiometry the following quantities of mass participate in the reaction:
- Na₂CO₃: 1 mole* 106 g/mole= 106 g
- CO₂: 1 mole* 44 g/mole= 44 g
- H₂O: 1 mole* 18 g/mole= 18 g
- NaHCO₃: 2 moles* 84 g/mole= 168 g
You can apply the following rule of three: if 106 grams of Na₂CO₃ are needed to produce 168 grams of NaHCO₃, how much mass of Na₂CO₃ is necessary to produce 1000 grams of NaHCO₃?
mass of Na₂CO₃= 630.95 grams
<u><em>630.95 grams of Na₂CO₃ would be needed to produce 1000g of NaHCO₃</em></u>
