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vagabundo [1.1K]
2 years ago
11

A 6.00 L container of N_2 has a temperature of 273 K. Calculate the volume if the temperature is doubled.

Chemistry
1 answer:
vfiekz [6]2 years ago
4 0
V1/T1 =V2/T2 (using charles law)

V1=6.00
V2=?
T1=273
T2=273

Making V2 the subject of formula the equation then becomes

V2= V1xT2/T1

6.00x263/273=6.0L
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