A 6.00 L container of N_2 has a temperature of 273 K. Calculate the volume if the temperature is doubled.

1 answer:

4 0

V1/T1 =V2/T2 (using charles law)

V1=6.00
V2=?
T1=273
T2=273

Making V2 the subject of formula the equation then becomes

V2= V1xT2/T1

6.00x263/273=6.0L

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