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vagabundo [1.1K]

2 years ago

11

A 6.00 L container of N_2 has a temperature of 273 K. Calculate the volume if the temperature is doubled.

1 answer:

vfiekz [6]2 years ago

4 0

V1/T1 =V2/T2 (using charles law)

V1=6.00
V2=?
T1=273
T2=273

Making V2 the subject of formula the equation then becomes

V2= V1xT2/T1

6.00x263/273=6.0L

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Which of the following is a non polar molecule ?

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3 years ago

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Nitella [24]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \:mass = 11.42 \:\: grams$

____________________________________

$\large \tt Solution \: :$

$\qquad \tt \rightarrow \: Q = ms\Delta T$

$\textsf{Q = heat evolved/absorbed = 501 J}$

$\textsf{m = mass in gram = ?}$

$\textsf{s = specific heat = 0.45}$

$\textsf{ΔT = change in temp = 120 - 22.5 =97.5°C}$

$\large\textsf{Find m : }$

$\qquad \tt \rightarrow \: 501 = m \sdot(0.45) \sdot(97.5)$

$\qquad \tt \rightarrow \: 501 = m \sdot43.875$

$\qquad \tt \rightarrow \: m = \dfrac{501}{43.875}$

$\qquad \tt \rightarrow \: m \approx11.42 \: \: g$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

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1 year ago

Zinc wire is added to an iron(II) nitrate solution.

Advocard [28]

Answer:

Zn(s) + Fe(NO₃)₂(aq) ⇒ Zn(NO₃)₂(aq) + Fe(s)

Explanation:

When metal zinc is added to an iron (II) nitrate solution, we can see the following redox reaction:

Zn(s) + Fe(NO₃)₂(aq) ⇒ Zn(NO₃)₂(aq) + Fe(s)

Zinc is oxidized since its oxidation number increases from 0 to +2.

Iron is reduced since its oxidation number decreases from +2 to 0.

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(b) Data has been collected to show that at a given wavelength in a 1 cm pathlength cell, Beer's Law for the absorbance of Co2+

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Explanation :

Using Beer-Lambert's law :

$A=\epsilon \times C\times l$

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l = path length

$\epsilon$ = molar absorptivity coefficient

From this we conclude that absorbance of solution is directly proportional to the concentration of solution at constant path length.

Thus, the relation between absorbance and concentration of solution will be:

$\frac{A_1}{A_2}=\frac{C_1}{C_2}$

Given:

$A_1$ = 0.350

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$C_1$ = 0.135 M

$C_2$ = ?

Now put all the given values in the above formula, we get:

$\frac{0.350}{0.460}=\frac{0.135}{C_2}$

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