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Anna007 [38]
2 years ago
10

A 40 g sample of water absorbs 500 calories of energy, how much did the water temp changed?​

Chemistry
1 answer:
Dafna1 [17]1 year ago
4 0

2.99 °C is the change in temperature if a 40 g sample of water absorbs 500 calories of energy.

<h3>What is specific heat capacity?</h3>

The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).

Given data:

m = 40 g

Q = 500 J

Specific heat capacity of water = 4.18 J/g°C

Change in Temperature =?

The formula for Heat Energy is given by:

Q = mcp∆T

where: Q - Heat Energy

m - mass

cp - specific heat

∆T = change in temperature, T_2 - T_1

Solution:

Substituting the value of m, specific heat capacity of water and Q in the formula,

500 J = (40 g)(4.18 J/g°C)(∆T)

∆T = 2.99 °C

Learn more about the specific heat capacity here:

https://brainly.ph/question/7099790

#SPJ1

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Molarity is given as;

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The reacting mass for sample B = 0.2175 mol x 58.5 g/mol = 12.72 g

The density of sample A  = \frac{mass}{volume} = \frac{17.55}{0.3} = 58.5 \ g/L

The density of sample B = \frac{mass}{volume} = \frac{12.72}{0.145} = 87.72 \ g/L

Therefore, sample B contains the larger density

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