Answer:
a) After the balloon inflated after 440 uL of dropwise due to the reaction of 1-Decene and the solution in the conical vial. b) 
⇒ 16
c) No 
was not the limiting reactant.
Explanation:
Generally, hydrogenation is the chemical reaction between a compound or element and molecular hydrogen in the presence of catalysts such as platinum.
a) After the balloon inflated after 440 uL of dropwise 1-Decene solution was added due to the reaction between 1-Decene and the solution in the conical vial.
b) ⇒ 16
c) was not the limiting reactant based on the mol to mol ratio of and decane which is 1:1. Therefore, if 0.8 mol of decane was produced then 0.8 mol of would also be produced.
<span>Ionic compounds are chemical compounds in which ions are held together in a lattice structure by ionic bonds. They have a high melting and boiling point, and they have a high hardness and are very brittle. The cations and anions are stuck together in a sense. So in this case, sodium (Na) is attracted to Chlorine (Cl).</span>
Selective uptake is the procedure with the aid of using which membranes in cells decide what molecules can cross in and what molecules can exit of a cell.
The studies aimed to expand chemically changed PIM-1s to be used in adsorption and fueloline separation processes. In particular, the nitrile institution in PIM-1 became transformed to numerous one of a kind purposeful organizations to control the interplay capacity of PIM-1 with one of a kind species. Synthesis of PIM-1 became done with the aid of using one of a kind methods, the usage of each the low (72h, 65 °C) and the excessive temperature (forty min, 160 °C) methods.
The response led to a aggregate of hydrolysis products. The composition of the polymer has a profound impact at the very last overall performance of the polymer. Powder samples of hydrolysed PIMs had been used withinside the studies. The discount of nitrile to number one amine became done the usage of borane dimethyl sulphide complex, ensuing in amine PIM-1.
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<h3><u>Answer;</u></h3>
<u>= 5 M or 5 moles/liter</u>
<h3><u>Explanation;</u></h3>
At point E, 90 g of substances X are dissolved in 100 g of the solvent.
100g of the solvent is equal to 100 ml
Molarity is the number of moles of a substance in one liter of a solvent.
90 g of X are in 100 ml
But; the RFM of X = 180 g/l
Therefore; the moles of X in 90 g = 90/180
= 0.5 moles
Therefore;
0.5 moles of X are contained in 100 ml of the solvent;
Thus, molarity = 0.5 × 1000/100
=<u> 5 M or 5 moles/liter</u>
