Temp must be Kelvin
38 C =
<span>
<span>
<span>
311.15
</span>
</span>
</span>
K
Volume at STP = 8.50 liters * (273.15 / 311.15) * (725 / 760) =
<span>
<span>
<span>
7.1182746306
</span>
</span>
</span>
Liters
The formula to use is:
Volume at STP = Present Volume * (273.15 / Present Temp °K) * (Present Pressure (Torr) / 760)
<u>Answer:</u> The standard potential of the cell is 0.77 V
<u>Explanation:</u>
We know that:

The substance having highest positive
reduction potential will always get reduced and will undergo reduction reaction.
The half reaction follows:
<u>Oxidation half reaction:</u> 
<u>Reduction half reaction:</u>
( × 2)
To calculate the
of the reaction, we use the equation:

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.
Putting values in above equation follows:

Hence, the standard potential of the cell is 0.77 V