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Monica [59]
3 years ago
6

Which physical method can be used for obtaining a sample of solid from a small beaker of salt water?

Chemistry
2 answers:
Makovka662 [10]3 years ago
6 0
I believe that the answer is B 100% sure

SOVA2 [1]3 years ago
3 0
Evaporation.  People have been doing that since ancient times to get salt from sea water.
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What would be the IUPAC name of PoTs2
Vikentia [17]

Answer:

6-methylhept-1-en-3-one

Explanation:

6 0
3 years ago
17 points help asap!! :) thank youuuu :) Jeff is in a stationary school bus. Which is the best reference point for him to use to
3241004551 [841]

Answer:

The answer would be A

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5 0
3 years ago
A sample of hydrogen gas is found to be 8.50 L at a temperature of 38.0 C and a pressure of 725mm Hg. Find the volume at STP.
Vsevolod [243]
Temp must be Kelvin
38 C = <span> <span> <span> 311.15 </span> </span> </span> K
Volume at STP = 8.50 liters * (273.15 / 311.15) * (725 / 760) =
<span> <span> <span> 7.1182746306 </span> </span> </span> Liters

The formula to use is:

Volume at STP = Present Volume * (273.15 / Present Temp °K) * (Present Pressure (Torr) / 760)

6 0
3 years ago
A galvanic (voltaic) cell consists of an electrode composed of nickel in a 1.0 M nickel(II) ion solution and another electrode c
Andre45 [30]

<u>Answer:</u> The standard potential of the cell is 0.77 V

<u>Explanation:</u>

We know that:

E^o_{Ni^{2+}/Ni}=-0.25V\\E^o_{Cu^{+}/Cu}=0.52V

The substance having highest positive E^o reduction potential will always get reduced and will undergo reduction reaction.

The half reaction follows:

<u>Oxidation half reaction:</u> Ni(s)\rightarrow Ni^{2+}(aq)+2e^-

<u>Reduction half reaction:</u> Cu^{+}(aq)+e^-\rightarrow Cu(s)       ( × 2)

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

Putting values in above equation follows:

E^o_{cell}=0.52-(-0.25)=0.77V

Hence, the standard potential of the cell is 0.77 V

5 0
3 years ago
Calculate the no. of moles in 25gm of calcium phosphate <br><br>Plz Fast Urgent
madreJ [45]

Answer:

0.162 mol

Explanation:

n=m/M

M= 20*3 + 15*2 + 8*4*2

M=154 g/mol

n=25g/154g/mol

n=0.162 mol

7 0
3 years ago
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