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Monica [59]
3 years ago
6

Which physical method can be used for obtaining a sample of solid from a small beaker of salt water?

Chemistry
2 answers:
Makovka662 [10]3 years ago
6 0
I believe that the answer is B 100% sure

SOVA2 [1]3 years ago
3 0
Evaporation.  People have been doing that since ancient times to get salt from sea water.
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Draw the simplified curved arrow mechanism for the reaction of butan-2-one and CH3Li to give the major product.
Yuki888 [10]

Answer:

Follows are the solution to this question:

Explanation:

Please find the image file of the chemical reaction in the attachment:

In a water medium, the CH3- type CH 3Li is a heavy nucleophile that attacks the carbonyl carbon atom to form the alkoxide ion, which will then be protonated to form alcohol.

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H2 + O2 ---&gt; H2O<br> Classifying reaction
Degger [83]

Answer:

hydrogen + oxygen = water

3 0
3 years ago
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During the combustion of 2.00 g of coal, the temperature of 500 g of water inside the calorimeter increased from 25.0°c to 43.7°
pantera1 [17]
Answer is: 39,083kJ.
m(coal) = 2,00g.
m(water) = 500g.
ΔT = 43,7°C - 25°C = 18,7°C, <span>difference at temperatures.</span>
c(water) = 4,18 J/g·°C, <span>specific heat of water
</span>Q = m(water)·ΔT·c(water), heat of reaction.
Q = 500g·18,7°C·4,18J/g·°C.
Q = 39083J = 39,083kJ.
6 0
3 years ago
How many moles are present in 54.8 mL of mercury if the density of mercury is 13.6 g/mL?​
lesya692 [45]

Answer:

3.72 mol Hg

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Density = Mass over Volume

Explanation:

<u>Step 1: Define</u>

D = 13.6 g/mL

54.8 mL Hg

<u>Step 2: Identify Conversions</u>

Molar Mass of Hg - 200.59 g/mol

<u>Step 3: Find</u>

13.6 g/mL = x g / 54.8 mL

x = 745.28 g Hg

<u>Step 4: Convert</u>

<u />745.28 \ g \ Hg(\frac{1 \ mol \ Hg}{200.59 \ g \ Hg} ) = 3.71544 mol Hg

<u>Step 5: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

3.71544 mol Hg ≈ 3.72 mol Hg

8 0
3 years ago
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