Answer:
Cellular differentiation is the process in which a cell changes from one cell type to another. Usually, the cell changes to a more specialized type. Differentiation occurs numerous times during the development of a multicellular organism as it changes from a simple zygote to a complex system of tissues and cell types.
Explanation: from google
The frequency and energy of most energetic of these photons is
Hz and 
J respectively.
The high energy photons will have least wavelength. Taking the given less wavelength for calculation of frequency and energy of photons.
λ = 2200 Å
Also, we know, 1 Å = 
m
So, λ = 
λ = 
<em> </em>m
Now, calculating frequency using the formula -
c = fλ, where c is speed of light, f is frequency and λ is wavelength.
We know, c = 
m/s
f = c/λ
f = 
frequency = Hz
Now, calculating Energy through the formula -
E = hf, where E is energy, h is planck's constant and f is frequency
Value of planck's constant = 
Js
E = *
Energy = J
Thus, frequency and energy of photons is Hz and J respectively.
Learn more about energy of photon -
brainly.com/question/15946945
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Answer: ![K_c=\frac{[CH_3Cl]\times [OH^-]}{[CH_3OH]\times [Cl^-]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCH_3Cl%5D%5Ctimes%20%5BOH%5E-%5D%7D%7B%5BCH_3OH%5D%5Ctimes%20%5BCl%5E-%5D%7D)
Explanation:
Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients. Pure solids are assumed to have a concentration of 1.
The given balanced equilibrium reaction is:
The expression for equilibrium constant for this reaction will be,
Thus the equilibrium constant expression for this reaction is
Answer:
The bond between Phosphorus and Chlorine in PCl3 is covalent as chlorine needs one electron and phosphorus has metallic character and easily donate electron
<span>0.228 g
The balance formula for the reaction between SrH2 and H2O is
SrH2(s) + 2 H2O(l) ==> Sr(OH)2(s) + 2 H2(g)
So for every mole of SrH2 used, 2 moles of hydrogen gas, or 4 moles of hydrogen atoms are released. So let's calculate the molar mass of SrH2 and H2O so see what the limiting reactant is.
strontium = 87.62
Hydrogen = 1.00794
Oxygen = 15.999
Molar mass of SrH2 = 87.62 + 2 * 1.00794 = 89.63588 g/mol
Molar mass of H2O = 2 * 1.00794 + 15.999 = 18.01488 g/mol
Moles of SrH2 = 5.06 g / 89.63588 g/mol = 0.056450609 mol
Moles of H2O = 4.34 g / 18.01488 g/mol = 0.240911957 mol
Looking at the balanced formula, for every mole of SrH2, it takes 2 moles of H2O. So the limiting reactant will be the SrH2. And for every mole of SrH2 used, we get 4 moles of hydrogen atoms. So
4 * 0.056450609 mole * 1.00794 g/mole = 0.227595307 g
Since we only have 3 significant figures, round the result to 3 figures, giving
0.228 g</span>
