The mass of bromine that would be formed is 639 g
<h3>Stoichiometry</h3>
From the question,
We are to determine how many grams of bromine would be formed
First, we will write the balanced chemical equation for the reaction,
The balanced chemical equation for the reaction is
F₂ + 2HBr → 2HF + Br₂
This means, 1 mole of fluorine reacts with 2 moles of HBr to produce 1 mole of bromine.
Then,
4.00 moles of fluorine will react with excess HBr to produce 4.00 moles of bromine.
Therefore,
The number of moles of bromine produced is 4.00 moles
Now, for the mass of bromine formed,
Using the formula,
Mass = Number of moles × Molar mass
Molar mass of bromine = 159.808 g/mol
Then,
Mass of bromine formed = 4.00 × 159.808
Mass of bromine formed = 639.232 g
Mass of bromine formed ≅ 639 g
Hence, the mass of bromine that would be formed is 639 g.
Learn more on Stoichiometry here: brainly.com/question/24691353
