What's 213Bi after undergoing alpha decay
1 answer:
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That will make a gold-202 nucleus.
<h3>Explanation</h3>Refer to a periodic table. The atomic number of mercury Hg is 80.
Step One: Bombard the with a neutron
. The neutron will add 1 to the mass number 202 of
. However, the atomic number will stay the same.
- New mass number: 202 + 1 = 203.
- Atomic number is still 80.
.
Double check the equation:
- Sum of mass number on the left-hand side = 202 + 1 = 203 = Sum of mass number on the right-hand side.
- Sum of atomic number on the left-hand side = 80 = Sum of atomic number on the right-hand side.
Step Two: The nucleus loses a proton
. Both the mass number 203 and the atomic number will decrease by 1.
- New mass number: 203 - 1 = 202.
- New atomic number: 80 - 1 = 79.
Refer to a periodic table. What's the element with atomic number 79? Gold Au.
.
Double check the equation:
- Sum of mass number on the left-hand side = 203 = 202 + 1 = Sum of mass number on the right-hand side.
- Sum of atomic number on the left-hand side = 80 = 79 + 1 = Sum of atomic number on the right-hand side.
A gold-202 nucleus is formed.
The process is not a redox reaction.
The reaction between ammonia and hydrochloric acid (HCl) to produce ammonium chloride (
) has modified the oxidation number of no atom in the reactants. As a base, ammonia interacts easily with hydrochloric acid to produce ammonium chloride salt. A neutralization reaction between an acid and a base is what the described process is, and it is NOT a redox reaction.
A reaction is referred to as a redox reaction if two or more reactants belonging to a single reaction exchange one or more electrons, i.e., one reactant releases one or more additional electrons while the other obtains one or additional electrons. The reacted substance that releases electrons is oxidized and becomes a reducing substance. A reduced oxidizing agent is the reactant that accepts electrons.
Learn more about redox reaction: brainly.com/question/13293425
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