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BlackZzzverrR [31]
2 years ago
5

A lead ball is added to a graduated cylinder containing 50.6 ml of water, causing the level of the water to increase to 93.0 mL.

What is the volume in milliliters of the lead ball, Vieras? Viead =
Chemistry
1 answer:
Kamila [148]2 years ago
4 0

42.4 ml is the volume in milliliters of the lead ball if a lead ball is added to a graduated cylinder containing 50.6 ml of water.

<h3>What is a graduated cylinder?</h3>

A tall narrow container with a volume scale is used especially for measuring liquids.

The graduated cylinder contains water

mL is a volume unit.

Water volume = 50.6 ml

The lead ball caused an increase in volume from 50.6 ml to 93.0 mL.

The new volume is the lead ball volume plus the original water volume :

Final volume = Vlead ball+ Water original volume

93.0 mL= V_(lead ball) +50.6 ml

V_(lead ball) = 93.0 mL - 50.6 ml

V_(lead ball) = 42.4 ml

Hence, 42.4 ml is the volume in milliliters of the lead ball.

Learn more about the graduated cylinder  here:

brainly.com/question/13386106

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In a particular experiment, the per cent yield is 79.0%. This means that in this experiment, a 7.90-g sample of fluorine yields is 7g of SF6.

<h3>How is Sulphur hexafluoride formed?</h3>

Sulfur Hexafluoride is a disparity agent formed of an inorganic fluorinated inert gas comprised of six fluoride atoms bound to one sulfur atom, with possible diagnostic activity upon imaging.

Thus, a sample of fluorine yields 7g of SF6.

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1 year ago
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Question 4 to make a 0.500 m solution, one could take 0.500 moles of solute and add 1.00 l of solvent. enough solvent to make 1.
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What would be the best way to measure the volume of a small ?​
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If 85.0 L of helium at 29.0°C is compressed to 32.0 L at constant pressure, what is the new temperature?
Feliz [49]

Answer:

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V1=85L of helium                         V2=32L

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