Answer:
Explanation:
Potential energy is energy due to position. It is the product of mass, height, and acceleration due to gravity.
The mass of the textbook is 1.85 kilograms. Assuming this is on Earth, the acceleration due to gravity is 9.8 meters per square second. The height is 2.23 meters.
- m= 1.85 kg
- g= 9.8 m/s²
- h= 2.23 m
Substitute the values into the formula.
Multiply the first 2 numbers together.
Multiply again.
- 1 kilogram square meter per square second (1 kg*m²/s²) is equal to 1 Joules (J)
- Our answer of 40.4299 kg*m²/s² is equal to 40.4299 J
The textbook has <u>40.4299 Joules of potential energy.</u>
Each shell can contain only a fixed number of electrons: The first shell
can hold up to two electrons, the second shell can hold up to eight (2 +
6) electrons, the third shell can hold up to18 (2 + 6 + 10) and so on.
The general formula is that the nth shell can in principle hold up to
2(n2) electrons.
Answer:
The eccentricity of the ellipse is 0.252.
Explanation:
The eccentricity of an ellipse (
), dimensionless, can be determined by means of the following expression:
(1)
Where:
- Distance between the foci, dimensionless.
- Length of the major axis, dimensionless.
If we know that 
and 
, then the eccentricity of the ellipse is:
The eccentricity of the ellipse is 0.252.
Answer:
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Answer:
- <u><em>You should expect that the ionic bond in LiBr is stronger than the bond in KBr.</em></u>
<u><em /></u>
Explanation:
The<em> ionic bonds</em> are formed by the electrostatic attraction between the ions, cations and anions.
In KBr the cation is K⁺ and the anion is Br⁻.
In LiBr the cation is Li⁺ and the anion is Br⁻.
You must expect that the bond strength depends mainly on the charges present on each ion and the distance between them.
Nevertheless, the effect of the distance between the radius dominate the trendency of the bond strength, which makes that the ionic strength trend be related to the ionic radius trend.
Lithium is a smaller ion than Potassium (both are in the same group and Lithium is above Potassium).
Thus, you should expect that the Li ion is closer to the Br ion than what the K ion is to the Br ion and expect that the bond between a Li ion and the Br ion be stronger than the bond between the K ion and the Br ion.
