Answer:
The volume of the balloon will be 5.11L
Explanation:
An excersise to solve with the Ideal Gases Law
First of all, let's convert the pressure in mmHg to atm
1 atm = 760 mmHg
760 mmHg ___ 1 atm
755.4 mmHg ____ (755.4 / 760) = 0.993 atm
922.3 mmHg ____ ( 922.3 / 760) = 1.214 atm
T° in K = 273 + °C
28.5 °C +273 = 301.5K
26.35°C + 273= 299.35K
P . V = n . R .T
First situation: 0.993atm . 6.25L = n . 0.082 . 301.5K
(0.993atm . 6.25L) / 0.082 . 301.5 = n
0.251 moles = n
Second situation:
1.214 atm . V = 0.251 moles . 0.082 . 301.5K
V = (0.251 moles . 0.082 . 301.5K) / 1.214 atm
V = 5.11L
Answer:
6.72 g
Explanation:
Given data:
Mass of calcium chlorate = 13.8 g
Mass of oxygen produced = ?
Solution:
Chemical equation:
Ca(ClO₃)₂ → CaCl₂ + 3O₂
Number of moles of calcium chlorate:
Number of moles = mass / molar mass
Number of moles = 13.8 g/ 206.98 g/mol
Number of moles = 0.07 mol
Now we will compare the moles of oxygen and calcium chlorate.
Ca(ClO₃)₂ : O₂
1 : 3
0.07 : 3×0.07=0.21 mol
Mass of oxygen:
Mass = number of moles × molar mass
Mass = 0.21 mol × 32 g/mol
Mass = 6.72 g
91 grams of sodium azide required to decompose and produce 2.104 moles of nitrogen.
Explanation:
2NaN3======2Na+3N2
This is the balanced equation for the decomposition and production of sodium azide required to produce nitrogen.
From the equation:
2 moles of NaNO3 will undergo decomposition to produce 3 moles of nitrogen.
In the question moles of nitrogen produced is given as 2.104 moles
so,
From the stoichiometry,
3N2/2NaN3=2.104/x
= 3/2=2.104/x
3x= 2*2.104
= 1.4 moles
So, 1.4 moles of sodium azide will be required to decompose to produce 2.104 moles of nitrogen.
From the formula
no of moles=mass/atomic mass
mass=no of moles*atomic mass
1.4*65
= 91 grams of sodium azide required to decompose and produce 2.104 moles of nitrogen.
It depends on the function and activity of both cells. Most normal cells crease division if they came into contact with other cells however the immune system interact directly with pathogens or foreign organisms to destroy them.
To find the number of neutrons, you subtract the atomic number from the mass number of element X. So in this case, it'll be 151-44= the number of neutrons.
