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vekshin1
3 years ago
13

Which method is adopted in the seperation of lead chloride from water​

Chemistry
1 answer:
Sergio039 [100]3 years ago
3 0

Explanation:

by dissolving the mixture of lead sulphate and lead chloride in water we can separate the two. after dissolving the mixture on water lead sulphate can be obtained as the solid that 's left behind lead chloride can be recovered by evaporating.

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Cell are the blank unit of all living organisms​
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Yes cells are the blank unit for all things that are living
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When solid water changes directly to water vapor without first becoming a liquid, the process is called?
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Sublimation. Sublimation is the change of a solid direct to gas or vapour without becoming liquid

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What does the group number on the periodic table tell you about the electron configuration of a
jarptica [38.1K]

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The group number in the periodic table represents number of valence electrons of the elements in a certain group.

Explanation:

There are s, p, d, and f blocks, which you can see in periodic table

The s-block and p-block together are usually considered main-group elements, the d-block corresponds to the transition metals, and the f-block encompasses nearly all of the lanthanides (like lanthanum) and the actinides (like actinium)

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Hope this helps!

4 0
3 years ago
How does Earth's rotation affect ocean currents?
Tom [10]

Answer:

Our planet's rotation produces a force on all bodies moving relative to theEarth. ... The force, called the "Coriolis effect," causes the direction of winds and ocean currents to be deflected.

Explanation:

4 0
2 years ago
Calculate the molarity of 48.0 mL of 6.00 M H2SO4 diluted to 0.250 L
const2013 [10]

Answer:

The answer is 1.15m.

Since molality is defined as moles of solute divided by kg of solvent, we need to calculated the moles of H2SO4 and the mass of the solvent, which I presume is water.

We can find the number of H2SO4 moles by using its molarity

C=nV→nH2SO4=C⋅VH2SO4=6.00molesL⋅48.0⋅10−3L=0.288

Since water has a density of 1.00kgL, the mass of solvent is

m=ρ⋅Vwater=1.00kgL⋅0.250L=0.250 kg

Therefore, molality is

m=nmass.solvent=0.288moles0.250kg=1.15m

4 0
3 years ago
Read 2 more answers
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