The molecular formula :
C₆H₁₄O₃PF
<h3>Further explanation</h3>
Given
39.10% carbon, 7.67% hydrogen, 26.11% oxygen, 16.82% phosphorus, and 10.30% fluorine.
Required
The molecular formula
Solution
mol ratio :
C = 39.1 : 12 = 3.258
H = 7.67 : 1 = 7.67
O = 26.11 : 16 = 1.632
P = 16.82 : 31 = 0.543
F = 10.3 : 19 = 0.542
Divide by 0.542
C = 6
H : 14
O = 3
P = 1
F = 1
The empirical formula :
C₆H₁₄O₃PF
(The empirical formula)n = the molecular formula
(C₆H₁₄O₃PF)=184.1
(6.12+14.1+3.16+31+19)n=184.1
(184)n=184.1
n = 1
Answer:
2.499 moles of sucrose
Explanation:
Divide by Avogadro's number
An element is defined as a substance made up of atoms with a specific number of protons.
Answer:
0.313 mole of NH3
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
2NH3(g) + 3CuO(s) → 3Cu(s) + N2(g) + 3H2O(g)
The number of mole of ammonia (NH3) required to react with 0.470 mole of copper(ll) oxide (CuO) can be obtained as follow:
From the balanced equation above,
2 moles of NH3 reacted with 3 moles of CuO.
Therefore, Xmol of NH3 will react with 0.470 mole of CuO i.e
Xmol of NH3 = (2 x 0.470) /3
Xmol of NH3 = 0.313 mole.
Therefore, 0.313 mole of NH3 is needed for the reaction
<u>Answer:</u> The solubility of ethylene gas in water is 
<u>Explanation:</u>
To calculate the molar solubility, we use the equation given by Henry's law, which is:
where,
= Henry's constant = 
= molar solubility of ethylene gas = ?
= partial pressure of ethylene gas = 0.684 atm
Putting values in above equation, we get:
Converting this into grams per liter, by multiplying with the molar mass of ethylene:
Molar mass of ethylene gas = 28 g/mol
So, 
Hence, the solubility of ethylene gas in water is
