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Sunny_sXe [5.5K]
1 year ago
8

What is the magnetic field due to a very very long wire with current A at a perpendicular distance 0.30000000000000004 m away fr

om the wire
Physics
1 answer:
abruzzese [7]1 year ago
4 0

The magnetic field due to a  very long wire with current A is 6.67 x 10⁻⁷ A (Tesla).

<h3>What is magnetic field?</h3>

This is the region of space where the effect of magnetic force is felt.

The magnetic field due to a current carrying conductor is calculated as;

B = μI/2πd

where;

  • μ is permeability of free space = 4π x 10⁻⁷ Tm/A
  • I is current in the conductor
  • d is the distance of field from the wire

at a distance of 0.3 m

B = μI/2π(0.3)

B = 0.53μI

B = 0.53 x (4π x 10⁻⁷)I

B = 6.67 x 10⁻⁷ A (Tesla)

Learn more about magnetic field here: brainly.com/question/7802337

#SPJ1

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Answer:

<h2>480</h2>

Explanation:

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4 0
2 years ago
Imagine you’re an engineer making a string of battery powered holiday lights. If a bulb burns out current cannot flow through th
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Answer:

The 2 light bulbs can be connected in parallel to each other to avoid disconnection when one bulb burns out.

Explanation:

The parallel connection is required not series. A parallel connection is the connection of electronic components (e.g bulbs, LED, resistors, capacitors etc) in such a way that the same voltage is supplied across the ends of the components.  While in a series connection, the components are connected to each other end-to-end.

As regard the question, parallel connection ensures that the brightness any of the bulbs is not affected with respect to the other bulbs. And other bulbs continue to function when any burns out. The 2 light bulbs should be connected in parallel to the baterry to avoid disconnection of all the bulbs.

4 0
3 years ago
a boy takes 15min to reach his school on bicycle.if the bicycle have speed of 2m/s the what is the distance between the house an
11111nata11111 [884]
When looking for distance you multiply speed by time

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6 0
3 years ago
The latent heat of fusion for Aluminium is 3.97 x 105. How much energy would be required to melt 0.75 kg of it?
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Answer:

E = 2.9775\times10^5 J

Explanation:

Given:  The latent heat of fusion for Aluminum is L = 3.97\times10^5  J/Kg

mass to be malted m = 0.75 Kg

Energy require to melt E = mL

E = 3.97\times10^5\times0.75 = 2.9775\times10^5 J

Therefore, energy required to melt 0.75 Kg aluminum

E = 2.9775\times10^5 J

5 0
3 years ago
A car with a mass of 1.50x10^3 kg starts from rest and accelerates to a speed of 18.0m/s in 12.0 s. assume that the force of res
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The first thing you should know for this case is the definition of distance.
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 answer:
 the average power developed by the engine is 23.9 kW
8 0
3 years ago
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