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Basile [38]
2 years ago
7

An electric motor uses 670 kJ of electrical energy to generate 595 kJ of mechanical kinetic energy. What is the efficiency of th

e motor?
Full example, please...
Thank you!
Physics
1 answer:
stellarik [79]2 years ago
4 0
  • Used energy=595KJ
  • Total energy=670KJ

Efficiency:-

\\ \tt\longmapsto \dfrac{595}{\cancel{670}}\times \cancel{100}

\\ \tt\longmapsto \dfrac{595}{67}\times 10

\\ \tt\longmapsto 8.88(10)

\\ \tt\longmapsto 88.8\%

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A bowling ball has a mass of 6 kg. What happens to its momentum when its speed increases from 2 m/s to 4 m/s?
mash [69]

Answer:

B) The initial momentum is 12 kg*m/s, and the final momentum is 24 kg*m/s

Explanation:

The momentum of an object is given by the product between its mass (m) and its velocity (v):

p=mv

Let's apply this formula to calculate the initial momentum and final momentum of the ball:

- initial momentum:

p_i = m v_i = (6 kg)(2 m/s)=12 kg m/s

- Final momentum:

p_f = m v_f = (6 kg)(4 m/s)=24 kg m/s

So, the correct answer is

B) The initial momentum is 12 kg*m/s, and the final momentum is 24 kg*m/s

3 0
2 years ago
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A charge of 9 pC is uniformly distributed throughout the volumebetween concentric spherical surfaces having radii of 1.6 cmand
balu736 [363]

Answer:

Electric Field = 3.369 x 10^4 N/C

Explanation:

Radius = r = (r1 + r2) / 2 = (1.6 + 3.6) /2 = 2.6 cm + 2.3 cm = 4.9 cm = 0.049 m

As we know, Electric field = E = kQ/r.r

= 8.98755 x 10^9 x 9 x 10^-9 / 0.049 x 0.049 = 33689.275 N/C

= 3.369 x 10^4 N/C

7 0
3 years ago
A ball is thrown straight up at 20 m. What is the balls velocity as it hits the ground?
deff fn [24]

Answer:

<em>The velocity of the ball as it hit the ground = 19.799 m/s</em>

Explanation:

Velocity: Velocity of a body can be defined as the rate of change of displacement of the body. The S.I unit of velocity is m/s. velocity is expressed in one of newtons equation of motion, and is given below.

v² = u² + 2gs.......................... Equation 1

Where v = the final velocity of the ball, g = acceleration due to gravity, s = the height of the ball

<em>Given: s = 20 m, u = 0 m/s</em>

<em>Constant: g = 9.8 m/s²</em>

<em>Substituting these values into equation 1,</em>

<em>v² = 0 + 2×9.8×20</em>

<em>v² = 392</em>

<em>v = √392</em>

<em>v = 19.799 m/s.</em>

<em>Therefore the velocity of the ball as it hit the ground = 19.799 m/s</em>

5 0
3 years ago
A cube of wood having an edge dimension of 20.0cm and a density of 650 kg /m³ floats on water. (b) What mass of lead should be p
schepotkina [342]

The mass added is "m" so the complete cube is submerged in the water is 2.8 kg.

<h3>What mass of lead should be placed on the cube?</h3>

Given: Side of the cube (a) = 20cm

The density of the cube (ρc) = $$650 kg/m^3

a) Applying the force balance, the buoyant force must be equal to the weight of the cube

ρcgV = ρg × (Ax)

Substituting the values in the above equation, we get

(650*(0.2 m)^3)=1000*(0.2 m)^2*x

x = 0.13

where x is the height of the cube in the water

$$A = a^2 is the area of the cross-section

ρ is the density of the water

V is the volume of the cube

Now, the height above the surface of the water would be

h = a − x

Substituting the values, then we get

h = 0.2 − 0.13

h = 0.07 m

b) The mass added is "m" so the complete cube is submerged in the water, therefore

ρcgV + mg = ρg × (V)

$(650*(0.2 m)^3)+m=1000*(0.2 m)^3

m = 2.8 kg

The mass added is "m" so the complete cube is submerged in the water is 2.8 kg.

To learn more about buoyant force refer to:

brainly.com/question/11884584

#SPJ4

7 0
1 year ago
What is the slope of the line plotted below?
lubasha [3.4K]

Answer:

Slope is in fact -2

Explanation:

Rise over Run

6 0
3 years ago
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