Ask question

Ask question

All categories

2 years ago

7

An electric motor uses 670 kJ of electrical energy to generate 595 kJ of mechanical kinetic energy. What is the efficiency of th

e motor?
Full example, please...
Thank you!

1 answer:

stellarik [79]2 years ago

4 0

Used energy=595KJ
Total energy=670KJ

Efficiency:-

$\\ \tt\longmapsto \dfrac{595}{\cancel{670}}\times \cancel{100}$

$\\ \tt\longmapsto \dfrac{595}{67}\times 10$

$\\ \tt\longmapsto 8.88(10)$

$\\ \tt\longmapsto 88.8\%$

You might be interested in

A box having a mass of 0.2 kg is dragged across a horizontal floor by

Lyrx [107]

you can check attachment for answer.

kind regards

7 0

3 years ago

What is the difference between delta and harbor?

Margarita [4]

The difference between delta and harbor is is that delta is the fourth letter of the modern greek alphabet while harbor is a sheltered expanse of water, adjacent to land, in which ships may dock or anchor, especially for loading and unloading.

5 0

3 years ago

A 2320 pound roller coaster starts from rest and is launched such that it creates a 110 ft high hill with a speed of 65 mph. The

Sergeu [11.5K]

Answer: E = 941738.537J

Explanation:

to begin,

given that the mass = 2320 pound = 1052.334 kg

Δh = 110 ft = 33.528 m

given that distance (d) = 1283 ft = 391.058 m

also the speed (v) is 65 mph = 29.058 m/s

force (F) = 87 pounds = 386.995 N

from our knowledge in work energy theory;

E = Fd + 1/2mv² + mgh

E = (386.995 × 391.058) + (1/2×1052.334×29.058²) + (1052.334×9.81×33.528)

E = 151337.491 + 444278.2 + 346122.84

E = 941738.537J

i hope this helps, cheers.

3 0

2 years ago

After observing a moth that is camouflaged against dark-colored bark, a scientist asks a question. The scientist discovers that

Rasek [7]

Because of how it's worded the answer would most likely be number four

6 0

3 years ago

Read 2 more answers

I have a voltage source of 12V but a light that only burns at 5V. The lamp works on 18 mA. Calculate the resistance that you EXT

ratelena [41]

Answer:

The resistance that will provide this potential drop is 388.89 ohms.

Explanation:

Given;

Voltage source, E = 12 V

Voltage rating of the lamp, V = 5 V

Current through the lamp, I = 18 mA

Extra voltage or potential drop, IR = E- V

IR = 12 V - 5 V = 7 V

The resistance that will provide this potential drop (7 V) is calculated as follows:

IR = V

$R = \frac{V}{I} = \frac{7 \ V}{18 \times 10^{-3} A} \ = 388.89 \ ohms$

Therefore, the resistance that will provide this potential drop is 388.89 ohms.

7 0

3 years ago