Answer:
-0.00152 V
Explanation:
Parameters given:
Diameter of the loop = 11 cm = 0.11m
Rate of change of magnetic field, dB/dt = 0.16 T/s
Radius of the loop = 0.055m
The area of the loop will be:
A = pi * r²
A = 3.142 * 0.055²
A = 0.0095 m²
The EMF induced in a loop of wire due to the presence of a changing magnetic field, dB, in a time interval, dt, is given as:
EMF = - N * A * dB/dt
In this case, there's only one loop, so N = 1.
Therefore:
EMF = -1 * 0.0095 * 0.16
EMF = -0.00152 V
The negative sign indicates that the current flowing through the loop acts opposite to the change in the magnetic field.
Answer:
The answer to your question is letter A. r = 1.07 x 10⁻¹⁴ m
Explanation:
Data
F = 2 N
d = ?
q = 1.6 x 10 ⁻¹⁹ C
k = 8.987 Nm²/C²
Formula
Solve for r
Substitution
Simplification
r = 
r = 
Result
r = 1.07 x 10⁻¹⁴ m
5 km northeast. Left and up would make northeast
Answer:
a. λ = 647.2 nm
b. I₀ 9.36 x 10⁻⁵
Explanation:
Given:
β = 56.0 rad , θ = 3.09 ° , γ = 0.170 mm = 0.170 x 10⁻³ m
a.
The wavelength of the radiation can be find using
β = 2 π / γ * sin θ
λ = [ 2π * γ * sin θ ] / β
λ = [ 2π * 0.107 x 10⁻³m * sin (3.09°) ] / 56.0 rad
λ = 647.14 x 10⁻⁹ m ⇒ λ = 647.2 nm
b.
The intensity of the central maximum I₀
I = I₀ (4 / β² ) * sin ( β / 2)²
I = I₀ (4 / 56.0²) * [ sin (56.0 /2) ]²
I = I₀ 9.36 x 10⁻⁵
The answer to the question is:
75m/s
Just do 25*3
