Answer:
ve = 8.06 x 10^5 m/s
vp = 1.882 x 10^4 m/s
Explanation:
K = 1.85 eV = 1.85 x 1.6 x 10^-19 J = 2.96 x 10^-19 J
me = 9.11 ✕ 10^-31 kg,
mp = 1.67 ✕ 10^-27 kg
Let the speed of electron is ve and the proton is vp.
For electron :
K = 1/2 me x ve^2
2.96 x 10^-19 = 0.5 x 9.11 x 10^-31 x ve^2
ve^2 = 6.498 x 10^11
ve = 8.06 x 10^5 m/s
For proton:
K = 1/2 mp x vp^2
2.96 x 10^-19 = 0.5 x 1.67 x 10^-27 x vp^2
vp^2 = 3.5449 x 10^8
vp = 1.882 x 10^4 m/s
Vapor lock
If your engine begins to lose power, run rough, stall, or refuse to start when traveling at high altitudes, your vehicle may be suffering from Vapor lock.
<h3>How is vapor lock fixed?</h3>
- By first pressing the accelerator pedal slightly (but not all the way to the floor) while starting the engine, you can aid in the removal of any vapor that may have remained in the fuel system after it has cooled.
- Hold down the accelerator pedal once the engine fires up until the car moves smoothly, which shows the vapor lock has passed.
<h3>What brings about a vapor lock?</h3>
- When fuel boils in the carburetor or fuel line, vapor lock results.
- Fuel that has vaporized stops gas from reaching your engine by creating back pressure in your fuel system.
- It frequently happens after idling or after turning off and back on a vehicle.
<h3>What is the duration of vapor lock?</h3>
- The heat builds up toward the gasoline lines as you shut down.
- Fuel in the lines could begin to evaporate in the absence of airflow through the cowling.
- Vapor lock typically occurs when you try to restart your aircraft after a sharp turn (shut down and restart after about 30 minutes).
To learn more about vapor lock visit:
brainly.com/question/28121377
#SPJ4
-- Light is electromagnetic radiation.
-- Electromagnetic radiation has no mass.
-- Electromagnetic radiation can travel through vacuum.
<span>(a)
Taking the angle of the pitch, 37.5°, and the particle's initial velocity, 18.0 ms^-1, we get:
18.0*cos37.5 = v_x = 14.28 ms^-1, the projectile's horizontal component.
(b)
To much the same end do we derive the vertical component:
18.0*sin37.5 = v_y = 10.96 ms^-1
Which we then divide by acceleration, a_y, to derive the time till maximal displacement,
10.96/9.8 = 1.12 s
Finally, doubling this value should yield the particle's total time with r_y > 0
<span>2.24 s
I hope my answer has come to your help. Thank you for posting your question here in Brainly.
</span></span>
Answer:
The final charges of each sphere are: q_A = 3/8 Q
, q_B = 3/8 Q
, q_C = 3/4 Q
Explanation:
This problem asks for the final charge of each sphere, for this we must use that the charge is distributed evenly over a metal surface.
Let's start Sphere A makes contact with sphere B, whereby each one ends with half of the initial charge, at this point
q_A = Q / 2
q_B = Q / 2
Now sphere A touches sphere C, ending with half the charge
q_A = ½ (Q / 2) = ¼ Q
q_B = ¼ Q
Now the sphere A that has Q / 4 of the initial charge is put in contact with the sphere B that has Q / 2 of the initial charge, the total charge is the sum of the charge
q = Q / 4 + Q / 2 = ¾ Q
This is the charge distributed between the two spheres, sphere A is 3/8 Q and sphere B is 3/8 Q
q_A = 3/8 Q
q_B = 3/8 Q
The final charges of each sphere are:
q_A = 3/8 Q
q_B = 3/8 Q
q_C = 3/4 Q
