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Nitella [24]
3 years ago
9

According to newtons third law, the two forces in a force pair act

Physics
1 answer:
aliina [53]3 years ago
6 0
B- Same force


It’s b because force always acts in equal but opposite pairs.
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A star is rotating at 5.55x10-5 π rad/s, its velocity decelerates at a constant rate of 0.5x10-9 π rad/s2.?
Basile [38]
<h2>The current rotational period of that star is 10.01 hours.</h2>

Explanation:

Given that,

Initial angular velocity of the star, \omega=5.55\times 10^{-5}\pi \ rad/s

It decelerates, final angular speed, \omega_f=0

Deceleration, \alpha =-0.5\times 10^{-9}\pi \ rad/s^2

It is not required to use the rotational kinematics formula. The angular velocity in terms of time period is given by :

\omega=\dfrac{2\pi}{T}

T is current rotational period of that star

T=\dfrac{2\pi}{\omega}

T=\dfrac{2\pi}{5.55\times 10^{-5}\pi \ rad/s}

T = 36036.03 second

or

1 hour = 3600 seconds

So, T = 10.01 hours

So, the current rotational period of that star is 10.01 hours. Hence, this is the required solution. Hence, this is the required solution.

4 0
3 years ago
Helppp meeee
worty [1.4K]
T = (v-0)/a
t = (45.5)/(9.8)
= 4.64m/s.

hope this helps :)
7 0
2 years ago
When should you use a piece of pipe as a leverage extension on the handle on a wrench?
Vesnalui [34]

Answer:

D

Explanation:

We must never use a piece of pipe as a leverage extension on the handle on a wrench.

Hence option d is correct.

7 0
3 years ago
Nina is doing a workout where she runs at 50% speed for 3 minutes, 75% speed for 2 minutes, and 100% speed for 30 seconds. This
Dovator [93]
D. Interval training
7 0
2 years ago
Read 2 more answers
Find the wavelength of the third line in the lyman series, and identify the type of em radiation.
Natalija [7]

The wavelength of the third line in the Lyman series, and identify the type of EM radiation

In this series, the spectral lines are obtained when an electron makes a transition from any high energy level (n=2,3,4,5... ). The wavelength of light emitted in this series lies in the ultraviolet region of the electromagnetic spectrum.

1 / lambda = R(h)* ( \frac{1}{(n1)^{2} } -   \frac{1}{(n2)^{2} })

                 = 109678 ( \frac{1}{1^{2} } -  \frac{1}{3^{2} } )

                 = 109678 (8/9)

   Lambda = 9 / (109678 * 8 )

                  = 102.6 * 10^{-9} m = 102.6 nm

To learn more about Lyman series here

brainly.com/question/5762197

#SPJ4

8 0
1 year ago
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