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Mariana [72]
2 years ago
14

Frieda stands on a hill with a slope of 62°. If her mass is 49 kg, what is the

Physics
1 answer:
olasank [31]2 years ago
5 0

Answer:

225.67 round to 226 (D)

Explanation:

just submitted on a.(p3*x

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A stone is dropped from a tower 100 meters above the ground. The stone falls past ground level and into a well. It hits the wate
Elan Coil [88]
Make the base of the building zero. Then the initial distance is 100m, final distance unknown x. Use gravity, time and initial velocity to solve for final distance.
x - 100 = (0)(5) +(1/2)(-9.81)(5^2)
x - 100 = 0 - 122.625
x = -122.625 + 100
x = -22.625 m below ground
7 0
3 years ago
Mixing of sand in water is an irreversible change true aur false​
USPshnik [31]

Answer:

<h3>true</h3>

Explanation:

<h3>hope it helps you ❤️</h3><h3>happy to help</h3>
3 0
2 years ago
A 0.041-kg bullet has a kinetic energy of 600j. What is the velocity of the bullet?
Paladinen [302]

171.0798 M/S

In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2.

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5 0
3 years ago
An electric heating element is connected to a 110v circuit and a current of 3.2 a is flowing through the element. How much energ
Kisachek [45]
2.580 Wh.... .........
7 0
3 years ago
Read 2 more answers
A diver stands on a diving platform 10.0 m above the surface of a pool and leaps upward with an initial speed of 2.5 m/s. how fa
Alexus [3.1K]
<span>The diver is heading downwards at 12 m/s Ignoring air resistance, the formula for the distance under constant acceleration is d = VT - 0.5AT^2 where V = initial velocity T = time A = acceleration (9.8 m/s^2 on Earth) In this problem, the initial velocity is 2.5 m/s and the target distance will be -7.0 m (3.0 m - 10.0 m = -7.0 m) So let's substitute the known values and solve for T d = VT - 0.5AT^2 -7 = 2.5T - 0.5*9.8T^2 -7 = 2.5T - 4.9T^2 0 = 2.5T - 4.9T^2 + 7 We now have a quadratic equation with A=-4.9, B=2.5, C=7. Using the quadratic formula, find the roots, which are -0.96705 and 1.477251164. Now the diver's velocity will be the initial velocity minus the acceleration due to gravity over the time. So V = 2.5 m/s - 9.8 m/s^2 * 1.477251164 s V = 2.5 m/s - 14.47706141 m/s V = -11.97706141 m/s So the diver is going down at a velocity of 11.98 m/s Now the negative root of -0.967047083 is how much earlier the diver would have had to jump at the location of the diving board. And for grins, let's compute how fast he would have had to jump to end up at the same point. V = 2.5 m/s - 9.8 m/s^2 * (-0.967047083 s) V = 2.5 m/s - (-9.477061409 m/s) V = 2.5 m/s + 9.477061409 m/s V = 11.97706141 m/s And you get the exact same velocity, except it's the opposite sign. In any case, the result needs to be rounded to 2 significant figures which is -12 m/s</span>
7 0
3 years ago
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