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yawa3891 [41]
3 years ago
9

5. If you walk 70 meters north in 5 minutes and 20 meters south in 15 seconds. What was the average

Physics
1 answer:
Tpy6a [65]3 years ago
3 0

Answer:

kjfvkuzfvnv

Explanation:

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The gas sample has now returned to its original state of 1.00 atm, 20.0 ∘c, and 1.00 l. what will the pressure become if the tem
steposvetlana [31]

At a constant volume and number of moles of the gas the ratio of T and P is equal to some constant. At another set of condition, the constant is still the same. Calculations are as follows:

T1/P1 = T2/P2

P2 = T2 x P1 / T1

P2 = 473.15 x 1.00 / 293.15

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3 years ago
What is the primary force that causes the seafloor to spread and continents to drift?
jekas [21]
The primary force would be Thermal Convection, it pushes it and thus makes continents drift.
-Hope that helps, Nexxmexx :3
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3 years ago
The internal pressure on a bottle of soda is 5550 torr. the bottle cap is designed to withstand a pressure of 7.2 atm. (a) calcu
Mademuasel [1]

This is a conversion problem. 760 Torr is equal to 1 atmosphere. so we can can solve now. 5,550torr*(1atmosphere/760torr)=7.3atmospheres. since the two torrs cancel out with cross multiplication we are left in atmosphere units.

6 0
3 years ago
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Interpret the following graph
tankabanditka [31]

Answer:

from O toWl Q partical is accelerating with constant magnitude. and from Q to P is decelerating with constant magnitude.

Explanation:

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3 0
2 years ago
A 16 kg science book is dropped of a 120 meter high cliff. Assuming a closed system:
Lapatulllka [165]

Answer:

Explanation:

The mass of that science book...wow. In pounds that would be 35.2! Yikes!

Anyway, we need final velocity here, and the mass of the book has nothing to do with how fast it falls. Everything is pulled by the same gravity. A feather falls at 9.8 m/s/s and so does an elephant. Mass is useless information. The equation we will use is

v^2=v_0^2+2aΔx  where

v is the final velocity, our unknown,

v₀ is the initial velocity which is 0 since someone had to be holding the book before dropping it,

a is the pull of gravity which is always -9.8 m/s/s, and

Δx = -120 which is the displacement (it's negative because the book falls below the point from which it was dropped). Filling in:

v^2=0^2+2(-9.8)(-120) so

v=\sqrt{2(-9.8)(-120)} and

v = 48 m/s

As far as how far above the bottom of the cliff the object is when it is moving at 12 m/s we will use the same equation, but the velocity will be 12:

12^2=0^2+2(-9.8)Δx and

144 = -19.6Δx so

Δx = -7.3 m. That's how far from the top of the cliff it is. We subtract then t find out how far it is from the bottom:

120 - 7.3 = 112.7 m off the ground.

6 0
3 years ago
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