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Anna007 [38]
3 years ago
7

Mixing of sand in water is an irreversible change true aur false​

Physics
1 answer:
USPshnik [31]3 years ago
3 0

Answer:

<h3>true</h3>

Explanation:

<h3>hope it helps you ❤️</h3><h3>happy to help</h3>
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What force (in N) must be exerted on the master cylinder of a hydraulic lift to support the weight of a 2400 kg car (a large car
makvit [3.9K]

Answer:

Fm= 91.88 N

Explanation:

Pascal principle

The pressure acting on one side is transmitted to all the molecules of the liquid because the liquid is incompressible.

The pressure is definited like this:

P=F/A

Where:

P: Pressure in pascals (Pa)

F: Force acting in the area  (N)

A  : Area where the force acts  (m²)

Pascal principle

Pm=Ps

Fm/ Am= Fs/ As  Formula (1)

Where :

Pm : Pressure on the master piston

Ps  : Pressure on the slave piston

Fm : Force on the master piston (N)

Fs:  Force on the  slave piston ((N)

Am: master piston area (m²)

As:  slave piston area  (m²)

Area Formula (A)

A= π*R²

R : piston radius

Calculation of the weight of the car (W)

W= m*g= 2400 kg*9.8m/s²= 23520 N

W = Fs

Data

Fs =  23520 N

Dm = 1.5 cm

Ds = 24 cm

Rm = 0.75 cm

Rs = 12 cm

Am = π*Rm² = π*(0.75)²

As = π*Rs² = π*(12)²

Force exerted on the master cylinder

We replace data in the formula (1)

\frac{F_{m} }{A_{m} } = \frac{F_{s} }{A_{s} }

F_{m}  = \frac{F_{s}*A_{m}  }{A_{s}}

F_{m} = \frac{(23520 N)*(\pi *(0.75)^{2})(cm^{2})}{(\pi *(12)^{2})(cm^{2})}

F_{m} = (23520 N)*\frac{(0.75)^{2} }{(12)^{2} }

Fm= 91.88 N

8 0
3 years ago
The froghopper, Philaenus spumarius, holds the world record for insect jumps. When leaping at an angle of 58.0° above the horizo
Jobisdone [24]

(a) 4.0 m/s

We can solve this part just by analyzing the vertical motion of the froghopper.

The initial vertical velocity of the froghopper as it jumps from the ground is given by

u_y = u_0 sin \theta (1)

where

u_0 is the takeoff speed

\theta=58.0^{\circ} is the angle of takeoff

The maximum height reached by the froghopper is

h = 58.7 cm = 0.587 m

We know that at the point of maximum height, the vertical velocity is zero:

v_y = 0

Since the vertical motion is an accelerated motion with constant (de)celeration g=-9.8 m/s^2, we can use the following SUVAT equation:

v_y^2 - u_y^2 = 2gh

Solving for u_y,

u_y = \sqrt{v_y^2-2gh}=\sqrt{-2(-9.8)(0.587)}=3.4 m/s

And using eq.(1), we can now find the initial takeoff  speed:

u_0 = \frac{u_y}{sin \theta}=\frac{3.4}{sin 58.0^{\circ}}=4.0 m/s

(b) 1.47 m

For this part, we have to analyze the horizontal motion of the froghopper.

The horizontal velocity of the froghopper is

u_x = u_0 cos \theta = (4.0) cos 58.0^{\circ} =2.1 m/s

And this horizontal velocity is constant during the entire motion.

We now have to calculate the time the froghopper takes to reach the ground: this is equal to twice the time it takes to reach the maximum height.

The time needed to reach the maximum height can be found through the equation

v_y = u_y + gt

Solving for t,

t=-\frac{u_y}{g}=-\frac{3.4}{9.8}=0.35 s

So the time the froghopper takes to reach the ground is

T=2t=2(0.35)=0.70 s

And since the horizontal motion is a uniform motion, we can now find the horizontal distance covered:

d=u_x T = (2.1)(0.70)=1.47 m

7 0
4 years ago
in a Mercury thermometer the level of Mercury Rises when its bulb comes in contact with a hot object what is the reason for this
olasank [31]

Answer:

because thermometric liquid readily expands on heating or contracts on cooling even for a small difference in the temperature of the body.

3 0
3 years ago
A student performs an experiment and must measure the lengths of four different objects: a textbook, a pencil, a cup, and a piec
Strike441 [17]
Most appropriate unit of measurement should be centimetres, cm.
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3 years ago
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Dimas [21]

Answer:

l and lll

Explanation:

4 0
3 years ago
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