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3 years ago

A 0.041-kg bullet has a kinetic energy of 600j. What is the velocity of the bullet?

Physics

1 answer:

Paladinen [302]3 years ago

5 0

171.0798 M/S

In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2.

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S Assume you have a battery of emf E and three identical lightbulbs, each having constant resistance R. What is the total power

slega [8]

The total power delivered by the battery if the lightbulbs are connected is 9V^2/R

<h3>Power of a battery</h3>

The formula for calculating the power of a battery is expressed according to the equation;

Power = v^2/RT

where

R is the total resistance

v is the voltage or emf

If there are 3 identical lightbulbs, each having constant resistance R, then;

1/RT = 1/R + 1/R + 1/R

1/RT = 3/R

RT = R/3

The voltage drop across each lightbulbs will be the same for parallel connection, hence;

Power = 3V^2/(R/3)

Power = 9V^2/R

Hence the total power delivered by the battery if the lightbulbs are connected is 9V^2/R

Learn more on power here: brainly.com/question/24858512

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8 0

1 year ago

The closest stars are 4 light years away from us. How far away must you be from a 854 kHz radio station with power 50.0 kW for t

Lubov Fominskaja [6]

Answer:

The distance from the radio station is 0.28 light years away.

Solution:

As per the question:

Distance, d = 4 ly

Frequency of the radio station, f = 854 kHz = $854\times 10^{3}\ Hz$

Power, P = 50 kW = $50\times 10^{3}\ W$

$I_{p} = 1\ photon/s/m^{2}$

Now,

From the relation:

P = nhf

where

n = no. of photons/second

h = Planck's constant

f = frequency

Now,

$n = \frac{P}{hf} = \frac{50\times 10^{3}}{6.626\times 10^{- 34}\times 854\times 10^{3}} = 8.836\times 10^{31}\ photons/s$

Area of the sphere, A = $4\pi r^{2}$

Now,

Suppose the distance from the radio station be 'r' from where the intensity of the photon is $1\ photon/s/m^{2}$

$I_{p} = \frac{n}{A} = \frac{n}{4\pi r^{2}}$

$1 = \frac{8.836\times 10^{31}}{4\pi r^{2}}$

$r = \sqrt{\frac{8.836\times 10^{31}}{4\pi}} = 2.65\times 10^{15}\ m$

Now,

We know that:

1 ly = $9.4607\times 10^{15}\ m$

Thus

$r = \frac{2.65\times 10^{15}}{9.4607\times 10^{15}} = 0.28\ ly$

5 0

2 years ago

A rock layer that stores and transmits water

lukranit [14]

The ability of the ground water to pass through the pore spaces in the rock is described as the rock's permeability. Permeable layers of rock that store and transport water are called aquifers.

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3 years ago

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Ivan

Answer:

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3 years ago

What is the amplitude of a wave related to

Vanyuwa [196]

Answer:

intensity because square of the amplitude is proportional to the intensity of the wave

Explanation:

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3 years ago