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ale4655 [162]
2 years ago
11

A diver stands on a diving platform 10.0 m above the surface of a pool and leaps upward with an initial speed of 2.5 m/s. how fa

st is the diver moving while falling past a diving board that is 3.0 m above the surface of the pool?
Physics
1 answer:
Alexus [3.1K]2 years ago
7 0
<span>The diver is heading downwards at 12 m/s Ignoring air resistance, the formula for the distance under constant acceleration is d = VT - 0.5AT^2 where V = initial velocity T = time A = acceleration (9.8 m/s^2 on Earth) In this problem, the initial velocity is 2.5 m/s and the target distance will be -7.0 m (3.0 m - 10.0 m = -7.0 m) So let's substitute the known values and solve for T d = VT - 0.5AT^2 -7 = 2.5T - 0.5*9.8T^2 -7 = 2.5T - 4.9T^2 0 = 2.5T - 4.9T^2 + 7 We now have a quadratic equation with A=-4.9, B=2.5, C=7. Using the quadratic formula, find the roots, which are -0.96705 and 1.477251164. Now the diver's velocity will be the initial velocity minus the acceleration due to gravity over the time. So V = 2.5 m/s - 9.8 m/s^2 * 1.477251164 s V = 2.5 m/s - 14.47706141 m/s V = -11.97706141 m/s So the diver is going down at a velocity of 11.98 m/s Now the negative root of -0.967047083 is how much earlier the diver would have had to jump at the location of the diving board. And for grins, let's compute how fast he would have had to jump to end up at the same point. V = 2.5 m/s - 9.8 m/s^2 * (-0.967047083 s) V = 2.5 m/s - (-9.477061409 m/s) V = 2.5 m/s + 9.477061409 m/s V = 11.97706141 m/s And you get the exact same velocity, except it's the opposite sign. In any case, the result needs to be rounded to 2 significant figures which is -12 m/s</span>
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What is the longest wavelength of radiation with enough energy to break carbon-carbon bonds?
iogann1982 [59]

The longest wavelength of radiation used to break carbon-carbon bonds is 344 nm.

<u>Explanation:</u>

The longest wavelength of radiation can also be stated as the minimum radiation frequency required to cut carbon-carbon bond should be equal to the threshold energy of the carbon-carbon bonds.

The threshold energy will be equal to the binding energy of the carbon-carbon bonds. As it is known that carbon-carbon bonds exhibit a binding energy of 348 kJ/mole, the threshold energy to break it, is determined as followed.

First, we have to convert the energy from kJ/mol to J, i.e., energy for the carbon-carbon molecules,

\text { Energy } = \frac{348 \mathrm{KJ} / \mathrm{mol}}{6.023 \times 10^{23} \text { photons }} \times 1 \text { mole } \times 1000 = 57.77 \times 10^{-20} = 5.78 \times 10^{-19} J

As,

         E=h v=\frac{h c}{\lambda}

So,

\lambda=\frac{h c}{E}=\frac{6.626 \times 10^{-34} \times 3 * 10^{8}}{5.78 \times 10^{-19}}=3.44 \times 10^{-7}

Thus, \lambda=344 \mathrm{nm} is the longest wavelength of radiation used to break carbon-carbon bonds.

5 0
3 years ago
A 50 kilogram woman wearing a seatbelt is traveling in a car that is moving with a velocity of +10 meters per second. In an emer
ra1l [238]

Answer:

the answer is A.) -1 * 10^3[N]

Explanation:

The solution consists of two steps, the first step is using the following kinematic equation:

v=v_{i} +a*t\\where:\\v=final velocity [m/s]\\v_{i}=initial velocity [m/s]\\a=acceleration[m/^2]\\t=time[s]\\

The initial velocity is 10 [m/s], and the final velocity is zero because the car stops in 0.5[s].

Replacing:

0=10+a*(0.5)\\a=-20[m/s^2]

Now in the second part, we need to use the second law of Newton, this law relates the forces with the acceleration of a body.

In the moment when the car stops suddenly the driver will feel the force of the seatbelt acting in the opposite direction of the movement.

F=m*a\\F=50[kg]*(-20[m/s^2])\\units\[kg]*[m/s^2]=[N]\\F=-1000[N] or -1*10^{3} [N]

The minus sign means that the force is acting in the opposite direction of the movement.

7 0
3 years ago
The temperature and pressure at the surface of Mars during a Martian spring day were determined to be -41 oC and 900 Pa, respect
Fittoniya [83]

Answer:

Part a)

\rho = 0.0205 kg/m^3

Part b)

\rho = 1.22 kg/m^3

So density of atmosphere at Martian Surface is very less than the density at Earth.

Explanation:

Part a)

As per ideal gas equation we know that

PM = \rho RT

here we know that Martian atmosphere is equivalent to that of carbon

so we will have

P = 900 Pa

T = 273 - 41 = 232 K

now we will have

(900)(0.044) = \rho (8.31)(232)

\rho = 0.0205 kg/m^3

Part b)

Now for the earth surface the density of air is given for

P = 101.6 kPa

T = 18 ^oC

so we will have

PM = \rho RT

(101.6\times 10^3)(0.029) = \rho(8.31)(273 + 18)

\rho = 1.22 kg/m^3

So density of atmosphere at Martian Surface is very less than the density at Earth.

8 0
2 years ago
According to Newton's Second Law of Motion, an object will accelerate if you apply what kind of force? Question 1 options: Frict
Bumek [7]

An unbalanced force is required to accelerate an object according to Newton's Second Law of Motion.

<h3>What does Newton's Second Law of Motion state?</h3>

It states that the force applied to the object is equal to the product of mass and acceleration.

F = ma

  • An object will accelerate when the net force applied on the object is more than zero or unbalanced.
  • The acceleration is the change in the direction or speed of the object. To achieve acceleration the force must be greater in a direction.

  • When force is greater in one the object move in that direction which is known as acceleration.

Therefore, an unbalanced force is required to accelerate an object according to Newton's Second Law of Motion.

Learn more about Newton's Second Law of Motion.:

brainly.com/question/25810165

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2 years ago
Which of the following forms of energy must an object have if it is moving at a constant velocity?
lbvjy [14]

Answer:

Kinetic energy

Explanation:

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