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Ksju [112]
3 years ago
14

Assuming the partial pressure of oxygen in air (0.20 atm) and nitrogen in air (0.80 atm). Calculate the mole fractions of oxygen

and nitrogen in water at 298 K. FOR THIS QUESTION report the mole fraction of OXYGEN
Chemistry
1 answer:
Nuetrik [128]3 years ago
6 0

Answer:

oxygen = 4.7 * 10^-6

Nitrogen = = 9.7 * 10^6

Explanation:

partial pressure of oxygen = 0.20 atm

partial pressure of Nitrogen = 0.80 atm

<u>calculate the mole fractions of oxygen and Nitrogen in water </u>

Temp = 298k

applying henry's law

molar conc of oxygen in water ( Coxygen )

= Kp = 1.3 * 10^-3 Mol/L.atm * 0.20 atm = 2.6 * 10^-4 Mol

molar conc of Nitrogen in water ( Cnitrogen )

= Kp = 6.8 * 10^-4 Mol/L.atm * 0.80 atm = 5.4 * 10^-4

next Given that the number of moles in 1 liter of water = 55.5 mol  

therefore the mole fraction of oxygen

= 2.6 * 10^-4 / 55.5

= 4.7 * 10^-6

mole fraction of Nitrogen

= 5.4 * 10^-4  / 55.5

= 9.7 * 10^6

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Cl-P=O
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6 0
3 years ago
Two experiments were conducted in a bomb calorimeter. The first one to determine the heat capacity of the calorimeter, the secon
Alex787 [66]

Answer: 2460J/g^0C

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=C\times \Delta T

Q = Heat absorbed by calorimeter =5682 Joules

C = heat capacity of calorimeter = ?

Initial temperature of the calorimeter = T_i = 22.37°C

Final temperature of the calorimeter = T_f  = 24.68°C

Change in temperature ,\Delta T=T_f-T_i=(24.68-22.37)^0C=2.31^0C

Putting in the values, we get:

5682=C\times 2.31^0C

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The heat capacity of the calorimeter is 2460J/g^0C

7 0
3 years ago
Give the stoichiometric coefficient for oxygen when the following equation is balanced using the lowest, whole-number coefficien
Mademuasel [1]

Answer: 2 \cdot CH_{4} O (l)+3 \cdot O_{2}(g) \rightharpoonup 2 \cdot CO_{2}(g) + 4 \cdot H_{2}O(l)

Explanation:

Let consider that one mole of diatomic oxygen is used. So, the stoichometric can be modelled by using three variables:

x \cdot CH_{4} O (l)+O_{2}(g) \rightharpoonup y \cdot CO_{2}(g) + z \cdot H_{2}O(l)

Where x,y,z are the required variables.

Now, three equations are constructed from the number of elements involved (Carbon, Hydrogen and Oxygen):

Carbon

x=y

Oxygen

x+2=2\cdot y + z

Hydrogen

4\cdot x = 2 \cdot z

The coefficients can be found by solving the abovementioned 3 x 3 Linear System:

x = \frac{2}{3}, y = \frac{2}{3}, z = \frac{4}{3}

The whole-number coefficients are determined by multiplying every coefficient by 3, then:

2 \cdot CH_{4} O (l)+3 \cdot O_{2}(g) \rightharpoonup 2 \cdot CO_{2}(g) + 4 \cdot H_{2}O(l)

4 0
3 years ago
How many molecules of SO₃ can be formed from 0.35 moles of O₂ (assuming excess SO₂) from the following UNBALANCED equation?
Dovator [93]

Molecules of SO₃  : 4.214 x 10²³

<h3>Further explanation </h3>

The reaction equation is the chemical formula of reagents and product substances  

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products  

Reaction(balanced)

2SO₂(g) + O₂(g) → 2SO₃(g)

mol SO₃ :

\tt mol~SO_3=\dfrac{2}{1}\times mol~O_2

\tt 2\times 0.35=0.7

number of molecules :

1 mol = 6.02 x 10²³ particles(atoms, molecules,ions)

\tt 0.7\times 6.02\times 10^{23}=4.214\times 10^{23}

5 0
3 years ago
Which of the following explains this observation?
NikAS [45]
It would be C i’m pretty sure
6 0
3 years ago
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