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const2013 [10]
2 years ago
9

An unknown substance can be identified by

Chemistry
1 answer:
kifflom [539]2 years ago
3 0
Are you asking if this is correct, or what the answer is?
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The majority of the elements in the Periodic Table are
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Most elements are metals. A.
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Density is given in ____. a. Pa/cm3 c. g/s2 b. N/m2 d. g/cm3 Please select the best answer from the choices provided A B C D
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Density is given in Mass/Volume so the answer is D
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3 years ago
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I NEED ANSWER PLEEEAASSEE!!!
emmasim [6.3K]
The answer is B. This is because Sodium has 1 valence electron and Fluorine has 7 valence electrons. All elements want 8 valence electrons so they may be stale, like the noble gases are. Hope this helps.
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3 years ago
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Suppose a student started with 142.0 mg of trans-cinnamic acid, 412 mg of pyridinium tribromide, and 2.30 mL of glacial acetic a
nirvana33 [79]

Answer: Theoretical Yield = 0.2952 g

               Percentage Yield = 75.3%

Explanation:

Calculation of limiting reactant:

n-trans-cinnamic acid moles = (142mg/1000) / 148.16 = 9.584*10⁻⁴ mol

pyridium tribromide moles = (412mg/1000) / 319.82= 1.288*10⁻³ mol

  • n-trans-cinnamic acid is the limiting reactant

The molar ratio according to the equation mentioned is equals to 1:1

The brominated product moles is also = 9.584*10⁻⁴ mol

Theoretical yield = (9.584*10⁻⁴ mol) * (Mr of brominated product)

                             =  (9.584*10⁻⁴ mol) * (307.97) = 0.2952 g

Percentage Yield is : Actual Yield / Theoretical Yield = 0.2223/0.2952

                                                                                           = 75.3%

4 0
3 years ago
The ph3 molecule is polar. does this offer experimental proof that the molecule cannot be planar? explain.
Alex
<span>Answer: if it was planar the center of the negative forces and the center of the positive forces would be at the same place, meaning no di-poles would form so it wouldnt be polar. as it is polar it therefore cannot be planar. the neagative center(pole) is above the the positive one due to the pair of unbonded electrons.</span>
7 0
3 years ago
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