Answer:
Hello, dear.
For the answer please see the explanation below.
Explanation:
The compressor power is:
2.212kW
(b) The refrigeration capacity is:
3.62 tons
(c) The coefficient of performance is:
5.75
The range of force exerted at the end of the rope is; 285.7 N to 1,000 N.
<h3>What is the Net horizontal force?</h3>
The net horizontal force of the cylinder when it is at equilibrium position can be found by applying Newton's second law of motion. Thus;
∑F = 0
F - μF_n = 0
We are given;
F_n = 5 kN = 5000 N
μ = 0.2
Thus;
F - 0.2(5,000) = 0
F - 1,000 = 0
F = 1,000 N
The strength of the applied force will be increasing as the number of turns of the rope increases. Thus;
Minimum force = Total force/number of turns of rope
Since rope is wrapped three and half times, then;
number of turns = 3.5
Thus;
minimum force = 1,000/3.5
minimum force = 285.7 N
Thus, the range of force exerted at the end of the rope is 285.7 N to 1,000 N.
Read more about net horizontal force at; brainly.com/question/26957287
Answer:
(A) Dry unit weight. = 15.71 kN/m³ =100.91 pcf
(B) Porosity = 40.82 %
(C) Degree of saturation = 66.52 %
(D) Weight of water, in pounds per cubic foot, to be added to reach full saturation = 81.22 pcf
Explanation:
(A) γd =
= 
KN/m³
(B) 
therefore 
1.69
Therefore e = 0.69 and
Porososity n = 
=
× 100% = 40.82 %
(C) 
therefore S =
= 
×100 = 66.52 %
(D) 
= 
= 19.68 kN/m³
The required amount of water is found from γ =ρ×g
ρ mass of water = 
1 kg/m³ = 0.062 pcf therefore 1301 kg/m³ = 1301 ×0.062 pcf or 81.22 pcf
Answer:
The resistance “seen” by the 12-Volt battery is 500 ohms . The total resistance is the sum of the resistors R1 and R2. Each resistor will drop a calculable amount of voltage. This voltage is given by Ohm's Law.
Answer:
A. By hit and trial method 280 C
Explanation:
ion know B sorry
