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irina1246 [14]
2 years ago
15

A rope is wrapped three and a half times around a cylinder. Determine the range of force T exerted on

Engineering
1 answer:
Mademuasel [1]2 years ago
7 0

The range of force exerted at the end of the rope is; 285.7 N to 1,000 N.

<h3>What is the Net horizontal force?</h3>

The net horizontal force of the cylinder when it is at equilibrium position can be found by applying Newton's second law of motion. Thus;

∑F = 0

F - μF_n = 0

We are given;

F_n = 5 kN = 5000 N

μ = 0.2

Thus;

F - 0.2(5,000) = 0

F - 1,000 = 0

F = 1,000 N

The strength of the applied force will be increasing as the number of turns of the rope increases. Thus;

Minimum force = Total force/number of turns of rope

Since rope is wrapped three and half times, then;

number of turns = 3.5

Thus;

minimum force = 1,000/3.5

minimum force = 285.7 N

Thus, the range of force exerted at the end of the rope is 285.7 N to 1,000 N.

Read more about net horizontal force at; brainly.com/question/26957287

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