Answer:
See attached picture.
Explanation:
See attached picture for explanation.
Answer:
For the two you haven't answered: (Drag greater than thrust, lift greater than weight) It will accelerate backwards (decelerate) and upwards
(Lift greater than weight, thrust greater than drag) accelerate upwards and forwards.
The load is 17156 N.
<u>Explanation:</u>
First compute the flexural strength from:
σ = FL / π
= 3000
(40
10^-3) / π (5
10^-3)^3
σ = 305
10^6 N / m^2.
We can now determine the load using:
F = 2σd^3 / 3L
= 2(305
10^6) (15
10^-3)^3 / 3(40
10^-3)
F = 17156 N.
Answer:
It is a non profit organization that dedicates to licensing professional engineers and surveyors
Explanation: