From the top of a vertical cliff 80m high, the angles of depression of 2 buoys lying due west of the cliff are 23° and 15° respe
1 answer:
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Answer:
a = 1.68m/
Explanation:
Please kindly find the attached file for explanations
Answer:
when 5% excess air is supplied, moles of air supplied/moles of fuel =
Explanation:
Equivalence ratio = 0.6
Equivalence ratio = Actual air to fuel ratio (AAFR)/ stoichiometric air to fuel ratio SAFR
combustion reaction of propane is
From above reaction, 1 mole of propane, from the reaction, 5 moles of oxygen required,
we know that air contains 21% O_2 and 79% N_2,
Therefore, moles of air based on stoichiometry
Theoretical air to fuel ratio
Given
Actual Air Fuel Ratio
when 5% excess air is supplied, moles of air supplied/moles of fuel =
Answer:
a. W = 51,194.54 kJ
b. W = 102,390 kJ
c. W = 153,585 kJ
Explanation:
a. the ground at 15°C.
=20°C = 273 K + 20 = 293 K
=15°C = 273 K + 15 = 288 K
W = 51,194.54 kJ
b. a pond at 10°C.
=10°C = 273 K + 10 = 283 K
W = 102,390 kJ
c. the outside air at 5°C.
=5°C = 273 K + 5 = 278 K
W = 153,585 kJ
Hope this helps!