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spayn [35]
2 years ago
13

From the top of a vertical cliff 80m high, the angles of depression of 2 buoys lying due west of the cliff are 23° and 15° respe

ctively. How far are the buoys apart?​
Engineering
1 answer:
Umnica [9.8K]2 years ago
6 0

Answer:

  110 m

Explanation:

The geometry of the problem can be modeled by a right triangle. The height of the cliff forms one leg, and the distance to a buoy forms the other leg. The angle of depression is opposite the height of the cliff. An appropriate trig relation is ...

  Tan = Opposite/Adjacent

Solving for the Adjacent side (the distance to the buoy), we find ...

  Adjacent = Opposite/Tan

  distance to buoy 1 = (80 m)/tan(23°) ≈ 188.468 m

  distance to buoy 2 = (80 m)/tan(15°) ≈ 298.564 m

Then the distance between the buoys is ...

  298.564 -188.468 m ≈ 110 m

The buoys are about 110 meters apart.

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A solid cylindrical workpiece made of 304 stainless steel is 150 mm in diameter and 100 mm is high. It is reduced in height by 5
goblinko [34]

Answer:

45.3 MN

Explanation:

The forging force at the end of the stroke is given by

F = Y.π.r².[1 + (2μr/3h)]

The final height, h is given as h = 100/2

h = 50 mm

Next, we find the final radius by applying the volume constancy law

volumes before deformation = volumes after deformation

π * 75² * 2 * 100 = π * r² * 2 * 50

75² * 2 = r²

r² = 11250

r = √11250

r = 106 mm

E = In(100/50)

E = 0.69

From the graph flow, we find that Y = 1000 MPa, and thus, we apply the formula

F = Y.π.r².[1 + (2μr/3h)]

F = 1000 * 3.142 * 0.106² * [1 + (2 * 0.2 * 0.106/ 3 * 0.05)]

F = 35.3 * [1 + 0.2826]

F = 35.3 * 1.2826

F = 45.3 MN

7 0
3 years ago
The advantages of solar cells include all of the following, except a.moderate net energy yield b.little or no direct emissions o
Xelga [282]

Answer:

C

Explanation:

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6 0
3 years ago
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Ratling [72]

Answer:

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Explanation:

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Tems11 [23]

Answer:

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6 0
3 years ago
CODE
zalisa [80]

Answer:

Explanation:

I'm not 100% this is what you want, but here it is:

2

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8

11

A

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