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Minchanka [31]
3 years ago
12

When an electric current is flowing through a wire, the force deflecting the charged particles is the greatest when the wire is

what to the magnetic field?
Physics
2 answers:
Makovka662 [10]3 years ago
5 0
The force is greatest when the wire is perpendicular to the magnetic field.

In fact, the expression for the magnetic force is
F=ILB \sin \theta
where I is the current, L the length of the wire, B the magnetic field intensity and \theta is the angle between the directions of I and B.

We can see that F is maximum when \sin \theta=1, so when \theta = 90^{\circ}, so when the wire and the magnetic field are perpendicular to each other.
zzz [600]3 years ago
3 0

Answer:

C.) perpendicular

Explanation:

A particle with an electric charge experiences the maximum deflecting force when it is positioned perpendicular to the magnetic field.

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If the absolute pressure of a gas is 550.280 kPa, its gage pressure is A. 101.325 kPa. B. 651.605 kPa. C. 448.955 kPa. D. 277.28
guajiro [1.7K]

Answer:

Option C is the correct answer.

Explanation:

Absolute  pressure is sum of gauge pressure and atmospheric pressure.

That is

               P_{abs}=P_{gauge}+P_{atm}

We have

          P_{abs}=550.280 kPa\\\\P_{atm}=1atm=101325Pa=101.325kPa

Substituting

         P_{abs}=P_{gauge}+P_{atm}\\\\550.280=P_{gauge}+101.325\\\\P_{gauge}=448.955kPa

Option C is the correct answer.

7 0
3 years ago
An object initially at rest experiences an acceleration of 9.8 m/s2. How much time will it take to achieve a velocity of 58 m/s?
frez [133]
5.91(approx) seconds just divide velocity by acceleration
4 0
4 years ago
Please answer the following question!
Semmy [17]

Answer:

0

Explanation:

the momentum will always be 0 when it is at rest because the object isnt moving!

Hope this helped!

6 0
2 years ago
The value of g is greater at the poles than at the equator why ​
babunello [35]

Answer:

because the gravitational pull is maximum at the poles and decreases as it comes down toward the equator.

6 0
3 years ago
Car A has a mass of 1,200 kg and is traveling at a rate of 22 km/hr. It collides with car B. Car B has a mass of 1,900 kg and is
anastassius [24]

The car A has a mass of 1200 kg.

The car B has the mass of 1900 kg.

It is given that velocity of car  A is given as 22 Km/hr

The car B has the velocity of 25 Km/hr.

Let the mass of two bodies are denoted as  m_{1} \ and\ m_{2}

Let the velocity of cars A and B are denoted as v_{1} \ and\ v_{2}

The momentum before collision is-

                                                  p_{i} =m_{1} v_{1} +m_{2} v_{2}

[Here p stand for momentum.]

We are asked to calculate the final momentum of the system after collision.

The answer of the question is based law of conservation of  linear momentum.

As per law of conservation of linear momentum the sum total linear momentum for an isolated system is always constant.Hence irrespective of the type of collision[elastic and inelastic],the momentum of the system is always constant which is a universal truth.

Let after the collision the velocity of A and B are v'_{1} \ and\ v'_{2}

Hence the final momentum of the system is-

                                                        p_{f} = m_{1} v'_{1} +m_{2} v'_{2}

As per the law of conservation of linear momentum, the initial and final momentum must be equal i.e      

                              p_{i} =p_{f}

                               m_{1} v_{1} +m_{2}v_{2} =m_{1} v'_{1} +m_{2} v'_{2}

Hence the option A  is right.

7 0
3 years ago
Read 2 more answers
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