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icang [17]
2 years ago
7

Physical data is often used in the court system. In fact, police officers use radar to determine your speed when you are driving

and admit that record in court if you are ever given a ticket. In one such instance, the police officer submitted data that goes against the claim of the driver, who is contesting his ticket in court. The police officer (who was stationary when he made the measure) claims that the driver was speeding at 44.7 m/s, but the driver claims he was only going 26.8 m/s (according to his speedometer). The speed limit was 60 mph. The driver argues that the radar gun must have been set incorrectly to record relative velocity. Is it possible that they are both telling the truth?
Physics
1 answer:
Mashcka [7]2 years ago
6 0

The driver is telling the truth, the radar gun must have been set incorrectly to record relative velocity.

The given parameters:

  • <em>Speed of the driver observed by the stationary police officer, Vo = 44.7 m/s</em>
  • <em>Speed of the driver, V = 26.8 m/s.</em>
  • <em>Speed limit = 60 mph</em>

The speed limit of the driver in meter per second is calculated as follows;

= 60 \ \times \frac{miles}{hour} \times \frac{1609.34 \ m}{1 \ mile} \times \frac{1 \ hr}{3600 \ s}\\\\= 26.82 \ m/s

From the speed limit, it is obvious that the driver's speed is within the limit. Thus, we can conclude that the driver is telling the truth, the radar gun must have been set incorrectly to record relative velocity.

Learn more about relative velocity here: brainly.com/question/17228388

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I = 24 A

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<h2>Ohm's Law</h2>

We will apply Ohm's Law to each resistor to find its current because we know the voltage across each resistor is 12 V  and the resistance of each resistor is 5Ω

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5 0
3 years ago
Refrigerant 134a enters a well-insulated nozzle at 200 lbf/in.2, 200°F, with a velocity of 120 ft/s and exits at 50 lbf/in.2 wit
riadik2000 [5.3K]

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x = 0.75801 = 75.801%

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94.344 = 35.715+ x \times 77.345

solving for x we get

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