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-BARSIC- [3]
2 years ago
9

PLEASE HELP ASAP! very much appreciated

Chemistry
1 answer:
soldier1979 [14.2K]2 years ago
3 0

Answer:

-Unknown

Explanation:

Questions is not seen properly bro

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At an ACME plant in Scottsdale Arizonia methanol is produced commercially
patriot [66]

Answer:

thats nice to know i will send Wile E. Coyote there for his supplys

Explanation:

4 0
3 years ago
Calculate the moles of 36.030 g of H2O.
lions [1.4K]

Answer: 1.99 mol h20

Explanation:

you have 36.030 g, trying to get it into mols

to get from g to mols, use the molar mass (periodic table)

36.030 g h20 (1 mol/18.02g) = 1.99 mol h20

4 0
3 years ago
¿Cuál es la carga eléctrica del átomo? Justificar.
Ksivusya [100]

Answer:

Es la cantidad de protones menos la cantidad de electrones.

Explanation:

Es la cantidad de protones menos la cantidad de electrones.

Por cierto, suscríbete a Kevin Tuna Music

8 0
3 years ago
Can any one please help me to answers this question i don't get it. thank in advance.
alex41 [277]
First, lets balance the reaction equation:
4Fe + 3O₂ → 2Fe₂O₃
It is visible form the equation that 4 moles of Fe require 3 moles of O₂
Molar ratio Fe/O₂ = 4/3 = 1.33
Molar ratio O₂/Fe = 3/4 = 0.75
Now, we check the molar ratios present:
Fe/O₂ = 6.8/8.9 = 0.76
O₂/Fe = 1.31

Thus, Iron is the limiting reactant because its ratio is not being fulfilled while the ratio of O₂ is surpassed.
8 0
3 years ago
A phosphate buffer solution (25.00 mL sample) used for a growth medium was titrated with 0.1000 M hydrochloric acid. The compone
AysviL [449]

Answer:

0,07448M of phosphate buffer

Explanation:

sodium monohydrogenphosphate (Na₂HP) and sodium dihydrogenphosphate (NaH₂P) react with HCl thus:

Na₂HP + HCl ⇄ NaH₂P + NaCl <em>(1)</em>

NaH₂P + HCl ⇄ H₃P + NaCl <em>(2)</em>

The first endpoint is due the reaction (1), When all phosphate buffer is as NaH₂P form, begins the second reaction. That means that the second endpoint is due the total concentration of phosphate that is obtained thus:

0,01862L of HCl×\frac{0,1000mol}{L}= 1,862x10⁻³moles of HCl ≡ moles of phosphate buffer.

The concentration is:

\frac{1,862x10^{-3}moles}{0,02500L} = <em>0,07448M of phosphate buffer</em>

<em></em>

I hope it helps!

7 0
4 years ago
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