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Mashutka [201]
3 years ago
13

Which method of galaxy formation is expected to dominate far in the future? (1 point

Chemistry
1 answer:
nevsk [136]3 years ago
6 0

Answer:

Dark Matter

Explanation:

90 percent of the mass in the universe is dark matter

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How do the differences in the polyatomic ions po3 3- and po4 3- help you determine whether each ends in -ite or -ate?
Tcecarenko [31]

There is a rule in naming polyatomic anions containing oxygen. Those names ending in <em>–ate</em> are given to the most common oxyanion of an element. While those names ending in <em>–ite</em> are for those that contains fewer O atom for the same charge. Since PPO_{3} ^{3-} has fewer O atoms, its name ends in <em>–ite</em>. Thus, PPO_{3} ^{3-}  is phosphite while PPO_{4} ^{3-}  is phosphate.

4 0
3 years ago
What is the volume of 2.1 moles of chlorine gas (Cl2) at standard temperature and pressure (STP)?
uysha [10]
Given:
<span> 2.1 moles of chlorine gas (Cl2) at standard temperature and pressure (STP)
Required:
volume of CL2
Solution:
Use the ideal gas law
PV = nRT
V = nRT/P
V = (2.1 moles Cl2) (0.08203 L - atm / mol - K) (273K) / (1 atm)
V = 47 L</span>
5 0
3 years ago
Please help ASAP!!!
alisha [4.7K]

Answer:

ye computer ka sawal he .

4 0
2 years ago
NEED HELP with 7. 8. 9. 10. 11. 12. And 14 !!
aleksley [76]

Answer:

1.      0.00040 calories

2.   8.57 calories

3.   0.196 calories

4.  68 calories

5. 243 calories

6.  83680 joules

7.  1,054,368 joules

8. 2.45 calories

9. 556 (it says calories to calories so it wouldn't change)

10. 28367.52 joules

11. 59.6 calories

12. 449.6 joules

13.  0.00234 calories

14. 23292.328 joules

15. 22877693.6 joules

Hope this helps!

Explanation:

6 0
3 years ago
The pH of a 1.0M solution of butanoic acid HC4H7O2 is measured to be 2.41. Calculate the acid dissociation constant Ka of butano
Lubov Fominskaja [6]

Answer:

Ka = 1.52 E-5

Explanation:

  • CH3-(CH2)2-COOH ↔ CH3(CH2)2COO-  + H3O+

⇒ Ka = [H3O+][CH3)CH2)2COO-] / [CH3(CH2)2COOH]

mass balance:

⇒<em> C</em> CH3(CH2)2COOH = [CH3(CH2)2COO-] + [CH3(CH2)2COOH] = 1.0 M

charge balance:

⇒ [H3O+] = [CH3(CH2)2COO-]

⇒ Ka = [H3O+]²/(1 - [H3O+])

∴ pH = 2.41 = - Log [H3O+]

⇒ [H3O+] = 3.89 E-3 M

⇒ Ka = (3.89 E-3)² / ( 1 - 3.89 E-3 )

⇒ Ka = 1.519 E-5

3 0
3 years ago
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