A plane leaves with an acceleration of 6.34 m/s squared and takes 1.5 hours to stop. What is the speed of the plane? What was th
1 answer:
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To solve this problem we will apply the geometric concepts of displacement according to the description given. Taking into account that there is an initial displacement towards the North and then towards the west, therefore the speed would be:
Travel north 2mph and west to 1mph, then,
The route is done exactly the same to the south and east, so make this route twice, from the definition of speed we have to
Therefore the total travel time for the man is 1.15hour.
Answer:
The final velocity of the object is, = 27 m/s
Explanation:
Given,
The acceleration of the object, a = 1000 m/s²
The initial displacement of the object, = 0 m
The final displacement of the object, = 0.75 m
The initial velocity of the object will be, = o m/s
The final velocity of the object, = ?
The average velocity of the object,
v = ( -
)/ t
= 0.75 / t
The acceleration is given by the relation
a = v / t
1000 m/s² = 0.75 / t²
t² = 7.5 x 10⁻⁴
t = 0.027 s
Using the I equation of motion,
= u + at
Substituting the values
= 0 + 1000 x 0.027
= 27 m/s
Hence, the final velocity of the object is, = 27 m/s