Answer:
The time taken by the wave to travel along the combination of two wires is 458 ms.
Explanation:
Given that,
Length of steel wire= 27.0 m
Length of copper wire = 48.0 m
Tension = 145 N
Radius of both wires = 0.450 mm
Density of steel wire 
Density of copper wire 
We need to calculate the linear density of steel wire
Using formula of linear density


Put the value into the formula


We need to calculate the linear density of copper wire
Using formula of linear density


Put the value into the formula


We need to calculate the velocity of the wave along the steel wire
Using formula of velocity



We need to calculate the velocity of the wave along the steel wire
Using formula of velocity



We need to calculate the time taken by the wave to travel along the combination of two wires


Put the value into the formula



Hence, The time taken by the wave to travel along the combination of two wires is 458 ms.