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alex41 [277]
4 years ago
5

The National High Magnetic Field Laboratory once held the world record for creating the strongest magnetic field. Their largest

hybrid magnet can produce a constant magnetic field of 45 T 45 T . To see if such a strong magnetic field could pose health risks for nearby workers, calculate the maximum acceleration the field could produce for Na + Na+ ions (of mass 3.8 × 10 − 26 kg 3.8×10−26 kg ) in blood traveling through the aorta. The speed of blood is highly variable, but 45 cm/s 45 cm/s is reasonable in the aorta.

Physics
1 answer:
Marina86 [1]4 years ago
5 0

Answer:

a = 85.3×10⁶ m/s²

Explanation:

Please see the attachment below.

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Which change to a circuit is most likely to decrease its electrical power?
Harlamova29_29 [7]

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It's D

Explanation:

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Can anyone check if my answer is correct ?
ohaa [14]

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4 0
3 years ago
A particle moves with a velocity    1 v 5j 3j 6k ms      under influence of a contact force  F 10i 10j 20k N.    
katrin2010 [14]

Answer:

P = 200 W

Explanation:

The expression for the power is

        P = W / t

the job

       W = F d

   

we substitute

      P = F d / t

      P = F. v

We apply this equation to our case where the velocity is

 v = (5 i + 3j + 6k) m / s

and the force is

 F = (10i + 10j +20 k) N

we substitute in the power equation, remember that the scalar product of the unit vectors is

i.i = j.j = k.k = 1 and the other products are zero

    P = 10 5 + 10 3 + 20 6

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6 0
3 years ago
A gas bottle contains 7.86×10^23 Oxygen molecules at a temperature of 327.0 K.
castortr0y [4]

Answer:

1.  E=5320.3J

2. E= 1773.45J

3. E=6.76*10^{-21}J

4. E=2.25*10^{-21}J

Explanation:

1. the thermal energy is given by the formula

E_T=\frac{3}{2}NK_BT=\frac{3}{2}(7.86*10^{23})(1.38*10^{-23}\frac{J}{K})(327.0K)=5320.3J

where KB is the Boltzmann's constant, T is the temperature and N is the number of molecules in the system.

2. Each degree of freedom contains one half of the total energy. Hence, the energy for one degree of freedom is

E_1=\frac{1}{2}NK_BT=1773.45J

3.

E=\frac{3}{2}K_BT=6.76*10^{-21}J

4.

E=\frac{1}{2}K_BT=2.25*10^{-21}J

Hope this helps!!

6 0
3 years ago
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