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alex41 [277]
3 years ago
5

The National High Magnetic Field Laboratory once held the world record for creating the strongest magnetic field. Their largest

hybrid magnet can produce a constant magnetic field of 45 T 45 T . To see if such a strong magnetic field could pose health risks for nearby workers, calculate the maximum acceleration the field could produce for Na + Na+ ions (of mass 3.8 × 10 − 26 kg 3.8×10−26 kg ) in blood traveling through the aorta. The speed of blood is highly variable, but 45 cm/s 45 cm/s is reasonable in the aorta.

Physics
1 answer:
Marina86 [1]3 years ago
5 0

Answer:

a = 85.3×10⁶ m/s²

Explanation:

Please see the attachment below.

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kotykmax [81]

We make a graphic of this problem to define the angle.

The angle we can calculate through triangle relation, that is,

sin\theta = \frac{c}{QP}\\sin\theta = \frac{c}{R}\\\theta=sin^{-1}\frac{c}{R}

With this function we should only calculate the derivate in function of c

\frac{d\theta}{dc} = \frac{1}{\sqrt{1-\frac{c^2}{R^2}}}(\frac{c}{R})'\\\frac{d\theta}{dc} = \frac{1}{\sqrt{R^2-c^2}}

That is the rate of change of \theta.

b) At this point we need only make a substitution of 0 for c in the equation previously found.

\frac{d\theta}{dc}\big|_{c=0} = \frac{1}{\sqrt{R^2-0}}\\\frac{d\theta}{dc}\big|_{c=0} = \frac{1}{R}

Hence we have finally the rate of change when c=0.

6 0
3 years ago
Why is Jupiter's rotation dangerous for human survivability?
krok68 [10]

Answer:

1. Why is Jupiter's rotation dangerous for human survivability?

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<em><u>Jupiter, like Venus, has an axial tilt of only 3 degrees, so there is literally no difference between the seasons. ... The length of each season is roughly three years. Jupiter is the fastest spinning planet in our Solar System, which causes the planet to flatten at the poles and bulge at the </u></em><em><u>equator.</u></em>

3.Why is the diameter of Jupiter an issue for human survivability?

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7 0
2 years ago
Which statement describes how the atoms in a conducting wire are organized?(1 point)
yulyashka [42]

Answer:

Positively charged nuclei are packed in an organized pattern, and the negatively charged valence electrons flow freely.

Explanation:

3 0
3 years ago
The escape velocity on earth is 11.2 km/s. What fraction of the escape velocity is the rms speed of H2 at a temperature of 31.0
Sveta_85 [38]

To solve this problem it is necessary to apply the concept related to root mean square velocity, which can be expressed as

v_{rms} = \sqrt{\frac{3RT}{n}}

Where,

T = Temperature

R = Gas ideal constant

n = Number of moles in grams.

Our values are given as

v_e =11.2km/s = 11200m/s

The temperature is

T = 30\°C = 30+273 = 303K

Therefore the root mean square velocity would be

v_{rms} = \sqrt{\frac{3(8.314)(303)}{0.002}}

v_{rms} = 1943.9m/s

The fraction of velocity then can be calculated between the escape velocity and the root mean square velocity

\alpha = \frac{v_{rms}}{v_e}

\alpha = \frac{1943.9}{11200}

\alpha = 0.1736

Therefore the fraction of the scape velocity on the earth for molecula hydrogen is 0.1736

7 0
3 years ago
At the instant the traffic light turns green, an automobile that has been waiting at an intersection starts ahead with a constan
oksian1 [2.3K]

Answer:

(A) Distance taken by automobile to overtake truck is 175.23 m

(B) Final speed of the automobile is 29.6 m/s.

Explanation:

According to the problem, the automobile is at rest, so its initial speed is zero and the automobile is moving with constant acceleration.

The general equation of motion is:

d = ut + 0.5at²      .....(1)

Here d is distance, a is acceleration, t is time and u is initial speed.

The distance (d₁) travel by the automobile after green light in time t is given by the relation :

d₁ = u₁t + 0.5at²

We know that its initial velocity is zero i.e. u = 0 m/s.

d₁ = 0.5at²      ......(2)

The truck is moving with constant speed, so its acceleration is zero. Therefore, the distance covered by the truck using equation (1) is;

d₂ = u₂t         .......(3)

Since, the distance travelled by automobile and truck are same. Hence,

d₁ = d₂

0.5at² = u₂t

t = 2u₂/a

Substitute 14.8 m/s for u₂ and 2.50 m/s² for a in the above equation.

t = \frac{2\times14.8}{2.50}

t = 11.84 s

(A) Distance travelled by automobile, d = u₂t =14.8 x 11.84 = 175.23 m

(B) Final speed of the automobile is given by the relation:

v = u + at

v = 0 + 2.50 x 11.84

v = 29.6 m/s

4 0
3 years ago
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