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seropon [69]
3 years ago
5

When atoms of an element are excited, they emit specific wavelengths of light. How is this similar to a fingerprint when Fraunho

fer lines are taken into account and useful for determining elements within a star?
Physics
1 answer:
Anika [276]3 years ago
7 0

Answer:

As you may know, each element has a "fixed" number of protons and electrons.

These electrons live in elliptical orbits around the nucleus, called valence levels or energy levels.

We know that as further away are the orbits from the nucleus, the more energy has the electrons in it. (And those energies are fixed)

Now, when an electron jumps from a level to another, there is also a jump in energy, and that jump depends only on the levels, then the jump in energy is fixed.

Particularly, when an electron jumps from a more energetic level to a less energetic one, that change in energy must be compensated in some way, and that way is by radiating a photon whose energy is exactly the same as the energy of the jump.

And the energy of a photon is related to the wavelength of the photon, then we can conclude that for a given element, the possible jumps of energy levels are known, meaning that the possible "jumps in energy" are known, which means that the wavelengths of the radiated photons also are known. Then by looking at the colors of the bands (whose depend on the wavelength of the radiated photons) we can know almost exactly what elements are radiating them.

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A 190 g air-track glider is attached to a spring. The glider is pushed in 8.6 cm against the spring, then released. A student wi
spin [16.1K]

Answer:

The spring constant = 9.25 N/m

Explanation:

The equation of an object attached to a spring that is oscillating is

T = 2π√(m/k)

Where T = period of the oscillation, m = mass of the object, k = spring constant.

Making k the subject of the equation,

k = 4π²m/T²......................... Equation 1

Note: Period(T) is the time taken to complete one oscillation

Given: T = t/10 = 9.0/10 = 0.9 s, m = 190 g = 0.19 kg.

Constant:  π = 3.14

Substitute these values into equation 1.

k = 4(3.14)²(0.19)/0.9²

k = 7.4933/0.81

k = 9.25 N/m

Thus the spring constant = 9.25 N/m

5 0
3 years ago
The whole body metabolic rate of a bottlenose dolphin is 8000kcalsday. The dolphin weighs 190kg. What is the mass specific metab
Komok [63]

Answer: 42.1

Explanation:

Mass specific metabolic rate of a dolphin can be defined as the rate at which the dolphin consume energy per unit mass of body weight.

R = E/M

Where R = mass specific metabolic rate

E = Energy consumption = 8000kcalsday

M = mass = 190kg

R = 8000kcalsday/190kg

R = 42.1

4 0
3 years ago
A rope is tied to a tree 4.5 feet from the ground and then run through a pulley hooked to a vehicle 33 feet from the tree. If a
Angelina_Jolie [31]

Answer:

The vehicle displacement is 9.90 feet.

Explanation:

Given that,

Height of tree = 4.5 feet

Distance = 33 feet

According to figure,

We need to calculate the value of l

Using Pythagorean theorem

l=\sqrt{(33)^2+(4.5)^2}

We need to calculate the vehicle displacement

Using horizontal component

Vehicle displacement =horizontal component of pulled rope

Vehicle\ displacement= d\cos\theta

Where, \theta is angle between rope and ground

d = pulled length of rope

Vehicle\ displacement=10\times\dfrac{33}{\sqrt{(33)^2+(4.5)^2}}

Vehicle\ displacement=9.90\ feet

Hence, The vehicle displacement is 9.90 feet.

3 0
3 years ago
Luke stands on the edge of a roof throws a ball downward. It strikes the ground with 100J of kinetic energy. Luke now throws ano
attashe74 [19]
A. Less than 100 this the answer
3 0
3 years ago
A particle moving on a circle has a velocity of 5 m/s and a normal acceleration of 10 m/s^2. What is the radius of the circle?
dybincka [34]

Answer:

Radius of the circle will be 2.5 m

Explanation:

We have given velocity of particle moving in the circle v = 5 m/sec

Acceleration of particle in the circle a=10m/sec^2

We have to find the radius of the circle

We know that acceleration is given by a=\frac{v^2}{r}

So 10=\frac{5^2}{r}

r=\frac{25}{10}=2.5m

So radius of the circle will be 2.5 m

3 0
3 years ago
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