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SashulF [63]
1 year ago
7

A current of 0.050 amps flows in a circuit element with a resistance of 25 ohms what is the voltage drop across the circuit elem

ent. (use ohms law V=IR)

Physics
1 answer:
katen-ka-za [31]1 year ago
3 0

The voltage drop across the circuit, given that 0.05 A flows in the circuit is 1.25 V

<h3>Ohm's law</h3>

This law states as follows:

V = IR

Where

  • V is the potential difference
  • I is the current
  • R is the resistor

<h3>How to determine the voltage</h3>

From the question given above, the following data were obtained:

  • Current (I) = 0.05 A
  • Resistance (R) =25 ohms
  • Voltage (V) =?

V = IR

V = 0.05 × 25

V = 1.25 V

Therefore, the voltage drop across the circuit is 1.25 V

<h3 />

Learn more about Ohm's law:

brainly.com/question/796939

#SPJ1

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displacement is given by equation

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time interval

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now the average velocity will be given as

v = \frac{\delta x}{\delta t}

v = \frac{1008}{4} = 252 m/s

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Malcolm and Ravi raced each other. The average of their maximum speeds was 260 km/h If doubled, Malcolm's maximum speed would be
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Answer

Given,

Average speed of Malcolm and Ravi = 260 km/h

Let speed of the Malcolm be X and speed of the Ravi Y.

From the given statement

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X + Y = 520 ....(i)

2X - Y = 80  ....(ii)

Adding both the equations

3 X = 600

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Putting value in equation (i)

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Which atomic number is the threshold value below which fusion may occur?
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Answer:

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Energy released in a fusion reaction is because of a key feature of nuclear matter called the binding energy which is a measure of the efficiency with which its constituent nucleons are bound together.

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A wire of length 5mm and Diameter 2m extends by 0.25 when a force of 50N was use. calculate the
bazaltina [42]

Answer and Explanation:

Data provided in the question

Force = 50N

Length = 5mm

diameter = 2.0m = 2\times 10^{-3}

Extended by = 0.25mm = 0.25\times 10^{-3}

Based on the above information, the calculation is as follows

a. The Stress of the wire is

= \frac{force\ applied}{area\ of \ circle}

here area of circle = perpendicular to the are i.e cross-sectional  i.e

= \frac{\pi d^{2}}{4}

= \frac{\pi(2\times 10^{-3})^2}{4}

Now place these above values to the above formula

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As 1Pa = 1 by N m^2

So,

MPa = 10^6 N m^2

b. Now the strain of the wire is

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= 5 \times 10^{-5}

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