The voltage drop across the circuit, given that 0.05 A flows in the circuit is 1.25 V
<h3>Ohm's law</h3>
This law states as follows:
V = IR
Where
- V is the potential difference
- I is the current
- R is the resistor
<h3>How to determine the voltage</h3>
From the question given above, the following data were obtained:
- Current (I) = 0.05 A
- Resistance (R) =25 ohms
- Voltage (V) =?
V = IR
V = 0.05 × 25
V = 1.25 V
Therefore, the voltage drop across the circuit is 1.25 V
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