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Minchanka [31]
3 years ago
5

In 1976, a 53 kg helicopter was built in Denmark. Suppose this helicopter flew east with a speed of 60.0 m/s and the total momen

tum of the helicopter and pilot was 7,200 kg∙m/s to the east. What was the mass of the pilot?
Physics
1 answer:
Bumek [7]3 years ago
6 0

Answer:

67 kg.

Explanation:

From the question,

Total momentum = (mass of the pilot+ mass of the helicopter)×velocity.

I = (m+M)v............................... Equation 1

Where I = Total momentum of the pilot and the helicopter, m = mass of the pilot, M = mass of the helicopter, v = velocity.

make m the subject of the equation

m = (I/v)-M.............................. Equation 2

Given: I = 7200 kg.m/s, v = 60 m/s, M = 53 kg.

Substitute these values into equation 2

m = (7200/60)-53

m = 120-53

m = 67 kg.

Hence the mass of the pilot is 67 kg

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Height is 7.05 m and not 7.05 mm

Answer:

9.603 m/s

Explanation:

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Since we want to find translational speed(v), let's get rid of ω.

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Divide through by m to get;

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Making v the subject gives;

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Answer:

0.48 m

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If the mass is hanging from equilibrium at 0.42 m above the floor, from the question, and it is then pulled 0.06 m below that particular position. This pulling is a means of adding more energy into the spring, when it is released, the weight compresses the spring and equals its distance (i.e, 0.06 m) above the height.

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