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Alex
3 years ago
11

A carpenter lifts a 10 kg piece of wood to his shoulder 1.5 m above the ground. What is the wood's potential energy on the carpe

nter's shoulder? (*Hint: "g" is the acceleration due to gravity of an object on Earth. G = 10 m/s^2)
Physics
1 answer:
Burka [1]3 years ago
8 0

Answer:

The wood's potential energy on the carpenter's shoulder is 150 J.

Explanation:

Given;

mass of the wood, m = 10 kg

height through which the wood was raised, h = 1.5 m

acceleration due to gravity, g = 10 m/s²

The  wood's potential energy on the carpenter's shoulder is calculated as;

P.E = mgh

P.E = 10 x 10 x 1.5

P.E = 150 J

Therefore, the wood's potential energy on the carpenter's shoulder is 150 J.

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Speed of light= wavelenght * frequency

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5 0
3 years ago
I need help!!!! I don’t understand physical science at all.
allochka39001 [22]
B is the correct answer
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Olivia is on a swing at the playground. if the swing is moving from W to Z, at which point is her kinetic energy increasing and
s2008m [1.1K]

Answer:

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Explanation:

hope this helps

4 0
3 years ago
During normal beating, a heart creates a maximum 3.95-mV potential across 0.305 m of a person’s chest, creating a 0.75-Hz electr
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Answer:

E = 0.0130 V/m.

Explanation:

The electric field is related to the potential difference as follows:

E = \frac{\Delta V}{d}

<u>Where:</u>

E: is electric field

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d: is the distance of a person's chest = 0.305 m

Then, the electric field is:

E = \frac{\Delta V}{d} = \frac{3.95 \cdot 10^{-3} V}{0.305 m} = 0.0130 V/m

Therefore, the maximum electric field created is 0.0130 V/m.

I hope it helps you!

7 0
3 years ago
A man stands on a platform that is rotating (without friction) with an angular speed of 1.0 rev/s; his arms are outstretched and
Airida [17]

Answer:

Explanation:

Given

N_1=1 rev/s

angular velocity \omega =2\pi N_1=6.284 rad/s

Combined moment of inertia of stool,student and bricks =6\ kg.m^2

Now student pull off his hands so as to increase its speed to suppose N_2 rev/s

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After Pulling off hands so final moment of inertia is

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I_1\omega _1=I_2\omega _2

6\times 6.284=2\times \omega _2

\omega _2=18.85\ rad/s

N_2=3 rev/s

7 0
3 years ago
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