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nignag [31]
2 years ago
14

The exterior of a solid cone is painted. The height of the cone is 11.4 centimeters, and the diameter of its opening is 5 centim

eters.
What is the surface area of the solid cone requiring paint to the nearest square centimeter?

The surface area of the solid cone requiring paint rounded to the nearest whole number is ___________ square centimeters.
Mathematics
2 answers:
almond37 [142]2 years ago
6 0

Answer:

111 cm^2

Step-by-step explanation:

h = 11.4

d = 5  so  r (radius) = 2.5

Surface Area of a Cone Formula: πr^2 + πrs

s represents the slant height of the cone, lets represent this with a drawing.

We have the values of h and r, but we don't have the value of s, meaning we have to find it. We can do this by using pythagorean theorem.

a^2 + b^2 = c^2

These three values can come together to create a right triangle which we can seperate from the rest of the diagram, now we can find s.

s = √(11.4^2 + 2.5^2)   so  s = 11.67

now that we have all of the pieces, we can plug back into the original surface area formula. πr^2 + πrs

π(2.5^2) + π(2.5)(11.67) = 111.29 cm^2 or 111 cm^2

RoseWind [281]2 years ago
5 0

Answer:

111 cm^2

Step-by-step explanation:

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