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2 years ago

Which of the following values are in the domain of the function graphed

Mathematics

1 answer:

Mice21 [21]2 years ago

6 0

Answer:

A. -2
B. -1
D. 0
E. 4

Step-by-step explanation:

The domain includes all x values, and here, it is [-2, 4].

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Tony wants to purchase a baseball glove for $14.96, a baseball bat for $19.87, and a baseball for $5.37. He figured out that he

Vanyuwa [196]

Reasonable because the three items altogether cost about $40

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3 years ago

Jerry is a judge. he hears 5 cases every 2 3/8 hours how many cases does he haer per hour

vampirchik [111]

Answer:

2 2/19

Step-by-step explanation:

5 cases in 2 3/8 hours

The unit rate of cases per hour is calculated by dividing the number of cases by the number of hours.

5/(2 3/8) = 5/(19/8) = 5 * 8/19 = 40/19 = 2 2/19

7 0

2 years ago

Read 2 more answers

Help I am very bad at math I need answers by tomorrow if you can help please do

d1i1m1o1n [39]

Answer:

Step-by-step explanation:

(a - b)(a +b) = a² - b²

1 - Sin² A = Cos² A

$LHS = \frac{1}{1- Sin A} + \frac{1}{1 + Sin A}\\\\= \frac{1*(1 + Sin A)}{(1- Sin A)(1 + Sin A)} + \frac{1*(1- Sin A)}{(1 + Sin A)(1- Sin A)}\\\\= \frac{1 + Sin A+ 1 - Sin A}{1^{2}- Sin^{2} A}\\\\= \frac{2}{1 - Sin^{2} A}\\\\= \frac{2}{Cos^{2} A}\\\\= 2 Sec^{2} A$

2) Sec² A - Tan² A = 1

$LHS = \frac{1}{Sec A - Tan A}\\\\=\frac{1*(Sec A + Tan A)}{(Sec A - Tan A)(Sec A + Tan A)}\\\\=\frac{Sec A + Tan A}{Sec^{2} A - Tan^{2} A}\\\\=\frac{Sec A + Tan A }{1}\\\\= Sec A + Tan A = RHS\\\\\\$

3) LHS = Cosec² A + Cot² A

= Cosec² A + Cosec² A - 1

= 2Cosec² A - 1 = RHS

$4) LHS = \frac{Sec A}{Cos A}- \frac{Tan A}{Cot A}\\\\ = Sec A*\frac{1}{Cos A}-Tan A*\frac{1}{Cot A}\\\\ = Sec A * Sec A - Tan A * Tan A\\\\= Sec^{2} A - Tan^{2} A \\\\= 1$

3 0

2 years ago

Janet was in an accident. The damage to her car is

Svet_ta [14]

hi tAnswer:hey

Step-by-step explanation:

7 0

2 years ago

ATCE Learning Center wants to make a net profit of $650,000 on the manual it sells to schools. The fixed costs for producing the

Elanso [62]

We are to solve for the price per unit. Let "x" be the price per unit.
The given values are the following:
Variable Cost = 1250,000 *x
Fixed Cost = $780,000
Net Profit = $650,000
Variable cost per unit = $19.85

The solution is shown below:
$650,000 = 1,250,000*x - $780,000 - $1,250,000*$19.85
x = $26, 242, 500 / 1,250,000 units
x = $20.994

The price per unit is $20.99 and the answer is letter "D".

6 0

2 years ago