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IgorC [24]
3 years ago
6

Carbonated drinks in cans have a small amount of space above the liquid level inside the can known as the “headspace.” What woul

d be true about the gas in this headspace if the can is opened? Volume stays constant. Pressure stays constant. Temperature stays constant.
Chemistry
2 answers:
andrey2020 [161]3 years ago
3 0
The temperature will stay constant.
SashulF [63]3 years ago
3 0

Answer: The temperature remains constant.

Explanation: Carbonated drinks have carbon dioxide mixed in water at high pressures as the solubility increases with high pressure. So, when we open the can at atmospheric pressure, the pressure will decrease and the solubility also decreases which will result in the increase in volume.

This phenomena is explained by Boyle's Law:

This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

Increase in pressure will result in decrease of volume and vice versa.

So, when we open the can of a carbonated drink, the pressure and volume changes but the temperature remains constant.

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enot [183]
Filtration

hope this helped
3 0
3 years ago
Detached earlobes are dominant, and are represented with a capital A. Attached earlobes are recessive, and are represented with
Aliun [14]
Attached earlobes are recessive, and are represented with a lowercase 
7 0
3 years ago
Determine the root-mean square speed of CO2 molecules that have an average kinetic energy of 4.2 x10-21 J per molecule.
strojnjashka [21]
<span>Determine the root-mean-square sped of CO2 molecules that have an average Kinetic Energy of 4.21x10^-21 J per molecule. Write your answer to 3 sig figs.
</span><span>
E = 1/2 m v^2 

If you substitute into this formula, you will get out the root-mean-square speed. 

If energy is Joules, the mass should be in kg, and the speed will be in m/s. 

1 mol of CO2 is 44.0 g, or 4.40 x 10^1 g or 4.40 x 10^-2 kg. 

If you divide this by Avagadro's constant, you will get the average mass of a CO2 molecule. 

4.40 x 10^-2 kg / 6.02 x 10^23 = 7.31 x 10^-26 kg 

So, if E = 1/2 mv^2 

</span>v^2 = 2E/m = 2 (4.21x10^-21 J)/7.31 x 10^-26 kg = 115184.68 
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8 0
3 years ago
According to the phase diagram for H₂O, what happens to the phases of
sergejj [24]

Answer:

"A", "water changes from a gas to a solid to a liquid", according to this phase diagram, at at 0°C, as pressure is increased from 0atm to 10atm.

Explanation:

The question asks what happens at 0°C, as pressure is increased from 0atm to 10atm.

According to the question, the temperature is held constant.  The pressure changes.  In the phase diagram, we find the temperature 0°C on the horizontal axis, and all points where the temperature are 0°C are along that vertical line.

Since the pressure starts at 0atm and increases to 10atm, we start at the bottom, and move upward along that line, to see what phases of matter the substance changes to.

At the bottom, it is initially in a "gas" phase.  As it moves up, it transitions to a "solid" phase.  Later, as it continues moving up, it changes again into a "liquid" phase.

Thus, the answer would be "A", "water changes from a gas to a solid to a liquid", according to this phase diagram, at at 0°C, as pressure is increased from 0atm to 10atm.

8 0
2 years ago
In the following reaction, how many liters of oxygen produce 560 liters of
saw5 [17]

The balanced chemical reaction will be:

CH4 + 2O2 → CO2 + 2H2O

We are given the amount of carbon dioxide to produce from the reaction. This will be our starting point.

 

560 L CH4 ( 1 mol CH4/ 22.4 L CH4 ) (2 mol O2/ 1 mol CH4 ) ( 22.4 L O2 / 1 mol <span>O2</span><span>) = 1120 L O2</span>

7 0
3 years ago
Read 2 more answers
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