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IgorC [24]
3 years ago
6

Carbonated drinks in cans have a small amount of space above the liquid level inside the can known as the “headspace.” What woul

d be true about the gas in this headspace if the can is opened? Volume stays constant. Pressure stays constant. Temperature stays constant.
Chemistry
2 answers:
andrey2020 [161]3 years ago
3 0
The temperature will stay constant.
SashulF [63]3 years ago
3 0

Answer: The temperature remains constant.

Explanation: Carbonated drinks have carbon dioxide mixed in water at high pressures as the solubility increases with high pressure. So, when we open the can at atmospheric pressure, the pressure will decrease and the solubility also decreases which will result in the increase in volume.

This phenomena is explained by Boyle's Law:

This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

Increase in pressure will result in decrease of volume and vice versa.

So, when we open the can of a carbonated drink, the pressure and volume changes but the temperature remains constant.

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Which group of elements ,in the periodic table, would most likely be used for electrical wires?
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What things are needed to form a hail storm?​
Basile [38]

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3 years ago
An unknown material has a mass of 5.75 g and a volume of 7.5 cm3.
Shtirlitz [24]

Hey there!:

Mass = 5.75 g

Volume = 7.5 cm³

Therefore:

Density = mass / volume

D = 5.75 / 7.5

D = 0.7 g/cm³

Answer C

Hope that helps!

3 0
3 years ago
If you have 1.29 moles of NaCl in 4 liters of solution, what is the molarity of the solution?
Illusion [34]

Answer:

0.32M

Explanation:

Given parameters:

Number of moles of NaCl  = 1.29moles

Volume of solution = 4liters  = 4dm³

Unknown:

Molarity of solution = ?

Solution:

Molarity is one the ways of expressing the concentration of a solute in a solution. It is given as;

         Molarity  = \frac{number of moles }{volume}

The unit is given as M which is mol/dm³

    Input the parameters and solve;

           Molarity  = \frac{1.29}{4}    = 0.32mol/dm³ or 0.32M

7 0
3 years ago
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