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scoray [572]
3 years ago
9

Two vectors have magnitudes 3 and 4 . how are the directions of the two vectors related if: a/the sum has magnitude 7.0 ​

Physics
1 answer:
Marina CMI [18]3 years ago
5 0
Same directions
Perpendicular
Opposite directions

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If the height is 10m, what is the potential energy? Asuming that the mass is 10
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\huge{\textit{\sf{{\color{m}{Answer}}{\color{b}{࿐}}}}}

we know,

\boxed{potential \: energy = mgh}

So,

\longmapsto10 \times 9.8 \times 10

\longmapsto980 \: joules

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What will happen when you slide the sponges in different directions?
Ede4ka [16]

Transform boundary

is the answer from stemscopes

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The fluid pressure 10 ft underwater is _____ the fluid pressure 5 ft underwater. A.less than or greater than, depending on what
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4 years ago
The heaviest weight ever lifted by a human ear is 51.7kg. how many pounds is this?
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4 years ago
A current of 16.0 mA is maintained in a single circular loop of 1.90 m circumference. A magnetic field of 0.790 T is directed pa
AVprozaik [17]

To solve this problem it is necessary to take into account the concepts related to the magnetic moment and the torque applied over magnetic moments.

For the case of the magnetic moment of a loop we have to,

\mu = IA

Where

I = Current

A = Area of the loop

Moreover the torque exerted by the magnetic field is defined as,

\tau = IAB

Where,

I = Current

A = Area of the loop

B = Magnetic Field

PART A) First we need to find the perimeter, then

P = 2\pi r

r = \frac{P}{2\pi}

r = \frac{1.9}{2\pi}

r = 0.3025m,

The total Area of the loop would be given as,

A = \pi r^2

A = \pi 0.3025^2

A = 0.287m^2

Substituting at the equation of magnetic moment we have

\mu = (16*10^{-3})(0.287)

\mu = 4.58*10^{-3} A.m^2

Therefore the magnetic moment of the loop is 4.58*10^{-3}Am^2

PART B)  Replacing our values at the equation of torque we have that

\tau = IAB

\tau = (16*10^{-3})(0.287)(0.790)

\tau = 3.62*10^{-3}Nm

Therefore the torque exerted by the magnetic field is 3.62*10^{-3}Nm

6 0
3 years ago
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