Answer:
Hi, Since energy levels in the nucleus are much higher than those in the gas, the nucleus will cool down by emitting a more energetic electromagnetic wave called a gamma ray . Gamma ray emission causes no change in the number of particles in the nucleus meaning both the atomic number and mass number remain the same.
It depends on the graphics, color, structure all that stuff for me to believe if the image is real or virtual
Hope I helped you
Answer:
Time, t = 0.87 seconds
Explanation:
Given that,
Initial velocity of the object, u = 4.3 m/s
The coefficient of kinetic friction between horizontal tabletop and the object is 0.5
We need to find the time taken by the object for the object to come to rest i.e. final velocity will be 0.
Using first equation of motion to find it as :

a is the acceleration, here, 


So, the time taken by the object to come at rest is 0.87 seconds. Hence, this is the required solution.
<u>Halfway</u><u> between the like poles of two magnets, because the field lines bend away and do not enter this area.</u>
How does a magnetic field diagram show where the field is strongest?
- The magnetic field lines do not ever cross.
- The lines include arrowheads to indicate the direction of the force exerted by a magnetic north pole.
- The closer the lines are to the poles, the stronger the magnetic field (thus the magnetic field from a bar magnet is highest closest to the poles).
Where is magnetic field the strongest and weakest on a magnet?
- The bar magnet's magnetic field is strongest at its core and weakest between its two poles.
- The magnetic field lines are densest immediately outside the bar magnet and least dense in the core.
Which two locations on the magnet would have the greatest attractive forces?
- Inside the magnet itself, the field lines run from the south pole to the north pole.
- The magnetic field is strongest in areas of greatest density of magnetic field lines, or areas of the greatest magnetic flux density.
Learn more about magnetic field
brainly.com/question/11514007
#SPJ4
<span>47 amu is the correct answer</span>