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Ber [7]
3 years ago
15

The acceleration of a cart rolling down a ramp depends on __________.

Physics
1 answer:
zmey [24]3 years ago
8 0

The angle that the cart rolls with the horizontal. The closer the ramp gets to 90 degrees the faster the cart will accelerate.

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Second and third class levers are differentiated by __________. a. the location of the fulcrum b. the location of the load c. th
strojnjashka [21]

Answer:

the answer is b

Explanation:

Second and third class levers are differentiated by <u>the location of the </u><u>load.</u>

<em>Hope</em><em> </em><em>this</em><em> </em><em>help</em><em> </em><em>you</em><em> </em><em>out </em><em>and have</em><em> </em><em>a </em><em>nice</em><em> </em><em>day </em><em>=</em><em>)</em>

5 0
2 years ago
The medical model of abnormality states that psychological disorders are __________.
I am Lyosha [343]
<span>A. social issues!
Hope this assists you!</span>
5 0
3 years ago
Read 2 more answers
What is the temperature 32 degrees Fahrenheit in degrees Celsius? A. 0°C B. 20°C C. 10°C D. –10°C
omeli [17]
The answer would 0. The reasoning of this is because freezing point in celsius is always 0 degrees but in fahrenheit the freezing point is 32 degrees.
8 0
3 years ago
A stone is thrown with an initial speed of 11.5 m/s at an angle of 50.0 above the horizontal from the top of a 30.0-m-tall build
rewona [7]

Answer:

The magnitude of the horizontal displacement of the rock is 7.39 m/s.

Explanation:

Given that,

Initial speed = 11.5 m/s

Angle = 50.0

Height = 30.0 m

We need to calculate the horizontal displacement of the rock

Using formula of horizontal component

v_{x}=u\cos\theta

Put the value into the formula

v_{x}=11.5\times\cos50

v_{x}=7.39\ m/s

Hence, The magnitude of the horizontal displacement of the rock is 7.39 m/s.

8 0
3 years ago
a spring gun initially compressed 2cm fires a 0.01kg dart straight up into the air. if the dart reaches a height it 5.5m determi
Vikki [24]

Answer:

2697.75N/m

Explanation:

Step one

This problem bothers on energy stored in a spring.

Step two

Given data

Compression x= 2cm

To meter = 2/100= 0.02m

Mass m= 0.01kg

Height h= 5.5m

K=?

Let us assume g= 9.81m/s²

Step three

According to the principle of conservation of energy

We know that the the energy stored in a spring is

E= 1/2kx²

1/2kx²= mgh

Making k subject of formula we have

kx²= 2mgh

k= 2mgh/x²

k= (2*0.01*9.81*5.5)/0.02²

k= 1.0791/0.0004

k= 2697.75N/m

Hence the spring constant k is 2697.75N/m

7 0
3 years ago
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