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3 years ago

Is this true or false the kinetic energy of a freely falling object decreases as it begins to fall

2 answers:

8 0

The kinetic energy of an object is the energy of the object as it moves. It has more kinetic energy the faster it moves. Because a falling object is increasing in speed, it would also increase in kinetic energy. Hope this helps! :)

rjkz [21]3 years ago

7 0

IT INCREASES AS IT STARTED TO FALL,
The kinetic energy = K.E = 1/2 * m *V^2
FROM THAT EQUATION, IT SAYS THAT THE K.E INCREASES AS THE VELOCITY INCREASE , SINCE IT FALLS SO IT WILL ACCELERATES, THAT MEANS THE VELOLCITY INCREASES, SO THE K.E INCREASE

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Which of the following statements is true? A. X-rays have longer wavelengths than microwaves. B. Radio waves have shorter wavele

3241004551 [841]

D is correct, Gamma rays have the shortest wavelength.

3 0

3 years ago

The speed of the 2 kg cart after 5 seconds is ? cm/s.

motikmotik

The answer to this question is 1cm/s

3 0

3 years ago

You stand on a merry-go-round which is spinning at f = 0:25 revolutions per second. You are R = 200 cm from the center. (a) Find

ivanzaharov [21]

Answer:

(a) ω = 1.57 rad/s

(b) ac = 4.92 m/s²

Explanation:

(a)

The angular speed of the merry go-round can be found as follows:

ω = 2πf

where,

ω = angular speed = ?

f = frequency = 0.25 rev/s

Therefore,

ω = (2π)(0.25 rev/s)

ω = 1.57 rad/s

(b)

The centripetal acceleration can be found as:

ac = v²/R

but,

v = Rω

Therefore,

ac = (Rω)²/R

ac = Rω²

therefore,

ac = (2 m)(1.57 rad/s)²

ac = 4.92 m/s²

(c)

In order to avoid slipping the centripetal force must not exceed the frictional force between shoes and floor:

Centripetal Force = Frictional Force

m*ac = μs*R = μs*W

m*ac = μs*mg

ac = μs*g

μs = ac/g

μs = (4.92 m/s²)/(9.8 m/s²)

μs = 0.5

7 0

3 years ago

Two people stand across from one another at the top edges of identical buildings, 50 meters above the ground. One person throws

cricket20 [7]

Answer:

Explanation:

Hope this helps!!!!

6 0

3 years ago

The wavelength of light that has a frequency of 1.20 × 1013 s-1 is ________ m.

klio [65]

The relationship between frequency and wavelength for an electromagnetic wave is
$c=f \lambda$
where
f is the frequency
$\lambda$ is the wavelength
$c=3 \cdot 10^8 m/s$ is the speed of light.

For the light in our problem, the frequency is $f=1.20 \cdot 10^{13} s^{-1}$ , so its wavelength is (re-arranging the previous formula)
$\lambda= \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{1.20 \cdot 10^{13} s^{-1}}= 2.5 \cdot 10^{-5}m$

8 0

3 years ago