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MAVERICK [17]
3 years ago
14

Is this true or false the kinetic energy of a freely falling object decreases as it begins to fall

Physics
2 answers:
Naddika [18.5K]3 years ago
8 0
The kinetic energy of an object is the energy of the object as it moves. It has more kinetic energy the faster it moves. Because a falling object is increasing in speed, it would also increase in kinetic energy. Hope this helps! :)
rjkz [21]3 years ago
7 0
IT INCREASES AS IT STARTED TO FALL, 
The kinetic energy = K.E =  1/2 * m *V^2  
FROM THAT EQUATION,  IT SAYS THAT THE K.E INCREASES AS THE VELOCITY INCREASE , SINCE IT FALLS SO IT WILL ACCELERATES, THAT MEANS THE VELOLCITY INCREASES, SO THE K.E INCREASE
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An ancient club is found that contains 100 g of pure carbon and has an activity of 6.5 decays per second. Determine its age assu
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The age of living tree is 11104 years.

Explanation:

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Activity of this carbon is = 6.5 decays per second = 6.5 x60 decays/min =390 decays/m

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R=\dfrac{-dN}{dt}=\lambda N=\dfrac{0.693}{t_{\frac{1}{2}}}N....(I)

Where, N = number of radio active atoms

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We need to calculate the number of radio active atoms

For N_{12_{c}}

N_{12_{c}}=\dfrac{N_{A}}{M}

Where, N_{A} =Avogadro number

N_{12_{c}}=\dfrac{6.02\times10^{23}}{12}

N_{12_{c}}=5.02\times10^{22}\ nuclie/g

For N_{c_{14}}

N_{c_{14}}=1.30\times10^{-12}N_{12_{c}}

N_{c_{14}}=1.30\times10^{-12}\times5.02\times10^{22}

N_{c_{14}}=6.526\times10^{10}\ nuclei/g

Put the value in the equation (I)

R=\dfrac{0.693\times6.526\times10^{10}\times60}{5700\times3.16\times10^{7}}

R=15.0650\ decay/min g

100 g carbon will decay with rate

R=100\times15.0650=1507\ decay/min

We need to calculate the total half lives

(\dfrac{1}{2})^{n}=\dfrac{390}{1507}

2^n=\dfrac{1507}{390}

2^n=3.86

n ln 2=ln 3.86

n=\dfrac{ln 3.86}{ln 2}

n =1.948

We need to calculate the age of living tree

Using formula of age

t=n\times t_{\frac{1}{2}}

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